Divide string into two parts based on separator in Scala

Question

input:

myString = ""FILTER=(ID=123,Description=456)""

output:

FILTER, (ID=123,Description=456)

basically divide the string into two parts How can i achieve this ?

Want something equivalent to str.partition(sep) as in python

The Archetypal Paul · Accepted Answer · 2015-12-16 20:43:43Z

4

You want split with a limit parameter (but you don't get the separator as an element as in the Python partition)

val myString = "FILTER=(ID=123,Description=456)"     
myString.split("=", 2)  
//> res0: Array[String] = Array(FILTER, (ID=123,Description=456))

It's actually a java method - see here

answered Dec 16, 2015 at 20:43

The Archetypal Paul

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Christian Hirsch · Accepted Answer · 2015-12-16 20:51:42Z

0

The span-method could also be helpful for you

   val myString = "FILTER=(ID=123,Description=456)"
   //myString: String = FILTER=(ID=123,Description=456)

   myString.span(_!='=')
   //res9: (String, String) = (FILTER,=(ID=123,Description=456))

answered Dec 16, 2015 at 20:51

Christian Hirsch

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1 Comment

The Archetypal Paul Over a year ago

That doesn't do what the OP stated (it leaves an extra separator at the start of the second string)

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