When I try to call a, b in function add, I get a is not defined even though I am returning the values. How do I make it return both a and b?
def numbers():
a= input ("a:")
a = int(a)
b= input ("b:")
b = int(b)
return a
return b
def add():
numbers()
print (a)
print (b)
add()
A return statement almost always causes a function to immediately terminate, and no other statement in the function will run. So once you return a, you'll never get to return b. You need to return both of them at the same time.
Additionally, returning a value from a function will not automatically put those names into the scope that called the function. You need to manually assign the values to something.
def numbers():
a= input ("a:")
a = int(a)
b= input ("b:")
b = int(b)
return a,b
def add():
a,b = numbers()
print (a)
print (b)
add()
I think so:
def numbers():
a= input ("a:")
a = int(a)
b= input ("b:")
b = int(b)
return a, b
def add(a, b):
print (a)
print (b)
return a, b
def main():
another_a, another_b = numbers()
another_a, another_b = add(another_a, another_b)
main()
add, the result from thenumbers()call needs to be assigned to local names, or else used directly. Callingnumbers()does not create localaandbvariables. The error message only complains aboutabecause the error causes the program to terminate; there is no opportunity to complain aboutb, but it would if it got that far.