how to fetch node elements from XML file by using xpath query,

Question

i want to fetch elements through search pattern like if i type "an" then i want all elements which have "an" example =man, animal, fan, pant

this is my code here i use foreach loop to display all search elements but i don't want to use foreach loop just i want to fetch all the list directly form xpath query please help me out its very impotent for me

private void Search2_Click_1(object sender, EventArgs e)
        {


            XmlNodeList nodes = myxml.DocumentElement.SelectNodes("/students/student/s_name" );

            string ha = search.Text;

            if (listbox11.Text == "Name")
            foreach(XmlNode node in nodes)
            {

                if(System.Text.RegularExpressions.Regex.IsMatch(node.InnerText,ha))
                { 
                    listBox1.Text += node.InnerText + "\r\n"; 
                }

            }

        }

Gokulakannan · Accepted Answer · 2015-12-22 06:33:21Z

1

Use this

private void Search2_Click_1(object sender, EventArgs e)
        {
  string ha = search.Text;

XmlNodeList nodes = myxml.DocumentElement.SelectNodes("/students/student/[contains(s_name,ha)]");

}

answered Dec 22, 2015 at 6:33

Gokulakannan

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2 Comments

krish Over a year ago

how to write same regular expression in VB6 ....is anything i need to add reference to run regular expression

krish Over a year ago

Dim ha As String ha = searchText.Text Set nodes = doc.documentElement.selectNodes("//s_name[descendant-or-self::*[contains(.,'" & ha + "')]]")

krish · Accepted Answer · 2015-12-22 07:21:25Z

0

**The code which i write is simple, xpath query will fetch only related elements nodes but if you want to print then use foreach loop **

private void Search2_Click_1(object sender, EventArgs e) {

       string ha = search.Text;

        if (listbox11.Text == "Name")
        {
            listBox1.Text = "";

            XmlNodeList nodes = myxml.DocumentElement.SelectNodes("//s_name[descendant-or-self::*[contains(.,'" + ha + "')]]");
            foreach (XmlNode node in nodes)
            {


                    listBox1.Text += node.InnerText + "\r\n";


            }
        }

    }

answered Dec 22, 2015 at 7:21

krish

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