PHP REGEX: Get domain from URL

Question

What I want

I want to get from a URL the domain part so from http://example.com/ -> example.com

Examples:

+----------------------------------------------+-----------------------+
| input                                        | output                |
+----------------------------------------------+-----------------------+
| http://www.stackoverflow.com/questions/ask   | www.stackoverflow.com |
| http://validator.w3.org/check                | validator.w3.org      |
| http://www.google.com/?q=hello               | www.google.com        |
| http://google.de/?q=hello                    | google.de             |
+----------------------------------------------+-----------------------+

I found some related questions in stackoverflow but none of them was exactly what I was looking for.

Thanks for any help!

This code will help you get the complete domain name: gist.github.com/praisedpk/64bdb80d28144aa78d58469324432277 — Hamid Sarfraz
– Hamid Sarfraz, Commented Sep 18, 2016 at 20:27

cletus · Accepted Answer · 2010-08-09 17:04:13Z

82

There's no need to use a regex for this. PHP has an inbuilt function to do just this. Use parse_url():

$domain = parse_url($url, PHP_URL_HOST);

answered Aug 9, 2010 at 17:04

cletus

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2 Comments

ewwink Over a year ago

it good only if containing http(s) , not for "stackoverflow.com/questions"

Jonathan Morales Vélez Over a year ago

this will also give you subdomains. Be careful because parse_url('http://example.com', PHP_URL_HOST) == parse_url('http://www.example.com', PHP_URL_HOST) will return false

aniski · Accepted Answer · 2016-05-17 14:52:36Z

4

I use:

$domain = parse_url('http://' . str_replace(array('https://', 'http://'), '', $url), PHP_URL_HOST);

Because parse_url doesn't return host key when schema is missing in $url.

edited May 17, 2016 at 14:52

aniski

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answered May 17, 2016 at 13:51

Marcin Żurek

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Comments

turbod · Accepted Answer · 2010-08-09 17:07:04Z

2

$tmp = parse_url($url);
$url = $tmp['host']

answered Aug 9, 2010 at 17:07

turbod

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Comments

Community · Accepted Answer · 2017-05-23 12:02:17Z

2

This is like the regex from theraccoonbear but with support for HTTPS domains.

if (preg_match('/https?:\/\/([^\/]+)\//i', $target_string, $matches)) {
  $domain = $matches[1];
}

edited May 23, 2017 at 12:02

CommunityBot

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answered Dec 6, 2013 at 8:29

fnkr

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Comments

Josh K · Accepted Answer · 2010-08-09 17:04:06Z

1

Assumes that http:// prefixes everything.

$tmp = explode("/", $url);
$domain = $tmp[2];

answered Aug 9, 2010 at 17:04

Josh K

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1 Comment

gnud Over a year ago

heh, most out-of-the-box solution :-)

Eugen Mihailescu · Accepted Answer · 2019-07-27 05:36:51Z

1

I think the following regexp might answers your question.

This diagram explains how it works, or rather why it works :-)

$regexp = '/.*\/\/([^\/:]+).*/';

// www.stackoverflow.com
echo preg_replace($regexp, '$1', 'http://www.stackoverflow.com/questions/ask');

// google.de
echo preg_replace($regexp, '$1', 'http://google.de/?q=hello');

// it works for the other input tests too ;-)

answered Jul 27, 2019 at 5:36

Eugen Mihailescu

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Comments

haydenmuhl · Accepted Answer · 2010-08-09 17:03:14Z

0

Here's my quick and dirty solution.

http://([^/]+).*

I haven't tested it, but it should grab anything between the http:// and the first slash.

answered Aug 9, 2010 at 17:03

haydenmuhl

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Comments

theraccoonbear · Accepted Answer · 2010-08-09 17:05:13Z

0

if (preg_match('/http:\/\/([^\/]+)\//i', $target_string, $matches)) {
  $domain = $matches[1];
}

answered Aug 9, 2010 at 17:05

theraccoonbear

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Comments

T.Todua · Accepted Answer · 2015-04-24 19:27:13Z

0

Best way i think:

preg_match('/(http(|s)):\/\/(.*?)\//si',  'http://www.example.com/page/?bla=123#!@#$%^&*()_+', $output);
// $output[0] ------------>  https://www.example.com/

answered Apr 24, 2015 at 19:27

T.Todua

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