php variable in to JSON object

Question

i'm doing this in codeigniter

here is my php switch - case part

case 'check':
$balance = $this->Model_transactions->getUserBalance($this->input->post('userId'));
$needToPay = floatval($this->input->post('tuitionRate')) / 2; // 50%
if ($balance >= $needToPay) {
$results = '{"Result": "OK";"Balance":'.$balance.'}';
}
break;

here is the json code

$.ajax({
url: base_url + "api/hires/check/?callback=?",
type: "POST",
dataType: "jsonp",
data: {
userId: $(".navigation").data("login"),
tuitionRate: t.find("#txt-hire-rate").val()
}
}).done(function (a) {
if (a) if ("OK" != a.Result) {
alert (a.Balance);

what i want is to use php $balance variable in my jQuery. please help.

Ohgodwhy · Accepted Answer · 2015-12-24 06:56:27Z

1

Do not try to build the string literal, instead, construct an array and use json_encode

$results = json_encode(array('Result' => 'OK', 'Balance' => $balance), true);

Then return it when you're ready.

return $results;

answered Dec 24, 2015 at 6:56

Ohgodwhy

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1 Comment

Dhan Over a year ago

got it Thank you! but how can i use this in jquery. here what i'm trying to do. .done(function (a) { var data = $.parseJSON(a); alert (data.Result);

Asif Jafri Mohammad Fahim · Accepted Answer · 2015-12-24 07:42:30Z

1

Edit your php script

case 'check':
$balance = $this->Model_transactions->getUserBalance($this->input->post('userId'));
$needToPay = floatval($this->input->post('tuitionRate')) / 2; // 50%
if ($balance >= $needToPay) {
$data = array(
  'Result' => 'OK',
  'Balance' => $balance 
);
echo json_encode($data);
}
break;

Edit your jQuery Script

$.ajax({
 type: "POST",
 url: '<?php echo base_url()."api/hires/check/?callback=?";?>',
 dataType: 'json',
 data:{userId: $(".navigation").data("login"),
 tuitionRate: t.find("#txt-hire-rate").val()},
 success: function(data){
            if(data.Result != "OK"){
                    alert(data.Balance);
            }
           }
 });

answered Dec 24, 2015 at 7:42

Asif Jafri Mohammad Fahim

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Comments

Nehal · Accepted Answer · 2015-12-24 08:01:37Z

php switch - case part

    case 'check':
    $balance = $this->Model_transactions->getUserBalance($this->input->post('userId'));
    $needToPay = floatval($this->input->post('tuitionRate')) / 2; // 50%
    if ($balance >= $needToPay) {
    $results = '{"Result": "OK";"Balance":'.$balance.'}';

    // add this in your code 
    <script>
       document.getelementbyId('balance').innerHTML=$balance;
    <script>
    }
    break;
    ?>
    <div id='balance' style='display:none;'></div> // added in the code

json code

var bal=$(#balance).html(); // use this variable where you want to
$.ajax({
url: base_url + "api/hires/check/?callback=?",
type: "POST",
dataType: "jsonp",
data: {
userId: $(".navigation").data("login"),
tuitionRate: t.find("#txt-hire-rate").val()
}
}).done(function (a) {
if (a) if ("OK" != a.Result) {
alert (a.Balance);

I did changes in php code and added the variable in js which can be used anywhere in js you want to.

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