how to display array values in php?

Question

im performing search from the database and displaying the result in the checkbox format in which when i select the checkbox the respectively values should be inserted in the another table which is in (a.php) since the search result have multiple values im storing the values in array but when im trying print the array with echo $_POST['friend']; it showing result as "Array" anyone help me how can i display the variables stored in array

<form method="post">
<div class="form-group">
    Name
    <br/>
    <input type="text" class="form-control" name="name"  />
    </div>
    <div class="form-group">
   Email <br/>
   <input type="text" class="form-control"name ="email"  />
   </div>
   <div class="form-group">
    Qualification<br/>
    <input type="text" class="form-control" name ="qualify" />
    </div>
    <input type="submit" value="Search" />

</form>
<?php
 $servername = "localhost";
$username = "root";
$password = "root";
$dbname = "myDB";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}
   $name=$_POST['name'];
 $email=$_POST['email'];
   $qualification=$_POST['qualify'];
 $sql = "SELECT * FROM form WHERE Name ='$name' OR EmailAddress = '$email' OR Qualification = '$qualification' ";
 $result=$conn->query($sql);

 if(!empty($_POST)) {
    if($result->num_rows === 0) 
{
  echo '<p style="margin-left:340px">no records</p>';
 }
} 



  while($row = $result->fetch_assoc())
 {
    //$_SESSION["snum"]=$row['sno'];
    //$_SESSION["nam"]=$row['Name'];
    //$_SESSION["quali"]=$row['Qualification'];
   // $_SESSION["emai"]=$row['EmailAddress'];

  echo '<br>';
  echo '<form name="friend" action="a.php" method="post">';
  echo '<input style="margin-left:340px;padding-bottom:10px" type="checkbox" name="friend[]">&nbsp;user Details</input>';
  echo '<br>';
  echo '<br>';
  echo '<div class="container" style="border-style:solid; border-width:medium;width: 550px;">';
  echo '<br>';
    echo 'Name: '.$row['Name']; 
    echo '<br /> EmailAddress: ' .$row['EmailAddress'];
    echo '<br /> Qualification: '.$row['Qualification'];
    echo '<br /> DOB: '.$row['DOB'];
    echo '<br/>';
    echo '<br/>';

    echo '<br/>';
    echo '<br/>';

    echo '</div>';
     echo '<br/>';
  }
  echo '<button type ="submit">invite</button>';
      echo '</form>';
$conn->close();    
?>

Possible duplicate of Display array values in PHP

Trevor
– Trevor

2015-12-28 06:47:00 +00:00
Commented Dec 28, 2015 at 6:47 — Trevor
– Trevor, Commented Dec 28, 2015 at 6:47

Manoj S Kadlag · Accepted Answer · 2015-12-28 06:44:09Z

1

Try this:

1.The print_r(variable); function is used to print human-readable information about a variable.

2.The var_dump(variable); function is used to display structured information (type and value) about one or more variables.

answered Dec 28, 2015 at 6:44

Manoj S Kadlag

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Comments

Arun Kumaresh · Accepted Answer · 2015-12-28 12:51:21Z

0

    <?php
     $servername = "localhost";
    $username = "root";
    $password = "root";
    $dbname = "myDB";

    // Create connection
    $conn = new mysqli($servername, $username, $password, $dbname);
    // Check connection
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    }

    $count=count($_POST['friend']);
    for($i=0; $i<$count; $i++)
    {
    $a=$_POST['friend'][$i];
    //echo $a;
     $sql = "SELECT Name,EmailAddress,Qualification FROM form WHERE sno='$a'";

    $result=$conn->query($sql);

    while($row = $result->fetch_assoc()){
     $ab=$row['Name'];
    $bc=$row['EmailAddress'];
    $ca=$row['Qualification'];
     echo $ab;
     echo'<br/>';
     echo $bc;
     echo'<br/>';
     echo $ca;
     echo'<br/>';

    $sql1="INSERT INTO arun ". "VALUES('$ab')";
    $result1=$conn->query($sql1);
    }
    }
    if (!$result) {
     //$_SESSION['message10'] = '<p style="color:green;margin-left: 250px";>Your request has been send </p>';

    //header("Location:send.php");
        echo "not send";
    }
     else {
    //   $_SESSION['message11'] = '<p style="color:red;margin-left: 250px";>you have already send request to the user</p>';

    //header("Location:new.php");
        echo "send";
        }
    $conn->close();
?>

edited Dec 28, 2015 at 12:51

Arun Kumaresh

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answered Dec 28, 2015 at 6:36

Nick

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3 Comments

Arun Kumaresh Over a year ago

Array ( [0] => on [1] => on [2] => on ) this is what printing when i use print_r($_POST['friend']); or var_dump($_POST['friend']) but i want to display the search result of Name,EmailAddress,Qualifiaction

Nick Over a year ago

Than you need put in form also something about this: ``<input type="hidden" name="id" value=".$row['id'].'">'. And check query SELECT * FROM form WHERE id in ( :id1, :id2, ...)` to search rows for each id, where $_POST['friend'][i] is on.

Arun Kumaresh Over a year ago

i have got the id but then how can the display the values

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