PHP : sending reset password link in email

Question

I am sending password reset link using html email in php. This is structure of my code. First is html email:

<?php $bodymessage= '<table border="0" cellpadding="0" cellspacing="0" width="100%" >;
 $bodoymessaage= .='<a href="$link"' .....?>

then I've setup heaeders

 <?php $headers  = 'MIME-Version: 1.0' . "\r\n";
    $headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
 ?>

and after this i recieve form fields and mail function like this

if($passreset){
       mail($to, $subject, $bodymessage, $headers);
}

now problem is that I've to get reset link and place it in html template thats being set in query and that comes after html template and headers , my questions is what should be order of template , headers and form query that i may get reset link in html template here $bodoymessaage= .='<a href="$link"' .....?>

Possible duplicate of PHP mail problem

Sagar Naliyapara
– Sagar Naliyapara

2015-12-30 07:29:21 +00:00
Commented Dec 30, 2015 at 7:29 — Sagar Naliyapara
– Sagar Naliyapara, Commented Dec 30, 2015 at 7:29

Praveen Kumar Purushothaman · Accepted Answer · 2015-12-30 07:26:03Z

3

When you use ', the variables are not expanded. So kindly use double quotes or, use string concatenation in PHP:

$bodoymessaage= .='<a href="$link"' .....?>
//--------------------------^^^^^ -- This doesn't work.

Change the above code to either:

$bodoymessaage= .="<a href=\"{$link}\"" .....?>         // Use double quotes Or
$bodoymessaage= .='<a href="' . $link . '"' .....?>   // String Concatenation

If you see how PHP Interprets Strings:

$var = "Var";
'$var';    // $var
"$var";    // Var
"{$var}"   // Var

edited Dec 30, 2015 at 7:26

answered Dec 30, 2015 at 7:23

Praveen Kumar Purushothaman

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11 Comments

Sikander Over a year ago

so will it get value that comes after this in order?

Praveen Kumar Purushothaman Over a year ago

@Sikander The main thing is the quotes buddy. Yes. Check the updated explanation.

Sikander Over a year ago

let me try this if it helps me ,

Praveen Kumar Purushothaman Over a year ago

@Sikander Yeah, please. If it works, don't forget to mark my answer. :)

bansi Over a year ago

I would mention "{$var}" is the best practice to replace variable in string.

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