78

Does anyone know how can I do a count in SQL Server based on condition.

Example:

How can I do a column count for records with name 'system', and total CaseID records in the table?

Customer table

UserID     CaseID     Name
1          100        alan
1          101        alan
1          102        amy
1          103        system
1          104        ken
1          105        ken
1          106        system

The result will display like below:

UserID    TotalCaseID    TotalRecordsWithSystem
1         7              2
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1
  • Why should you not use WHERE name = 'system'? Commented Nov 7, 2017 at 23:50

4 Answers 4

Reset to default
163

Use SUM/CASE...

SELECT
    COUNT(*),  --total
    SUM(CASE WHEN name = 'system' THEN 1 ELSE 0 END) --conditional
FROM
    myTable
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4 Comments

Oh the old good SUM CASE... Always so helpful, always so easy to forget about. Thank you!
ELSE 0 END doesn't work for me. I have to use ELSE null END as per @kage 's answer
@SebastianJ. probably because you used COUNT() on the CASE WHEN .. THEN .. ELSE .. END construction. If you use SUM() as shown it will work just fine.
SELECT COUNT(*) FROM myTable WHERE name='system' works too, no need for CASE WHEN
17

I think he wanted user id in the results

SELECT 
    userid,
    COUNT(*) as TotalcaseID, --total 
    SUM(CASE WHEN name = 'system' THEN 1 ELSE 0 END) as TotalRecordsWithSystem  
FROM 
    myTable 
group by userid
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1 Comment

At that, example output shows TotalCaseID, too.
9 
select
userid,
count('x') as TotalCaseID,
count(case when name = 'system' then 'x' else null end) as TotalRecordsWithSystem
from CustomerTable
group by userid
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Comments

9

If you're on SQL Server 2012+, then you can use SUM/IIF

SELECT
    COUNT(*) AS Total,
    SUM(IIF(Name = 'system', 1, 0)) AS SystemTotal
FROM
    CustomerTable
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