Add a total to output of bash script

Question

I am running a bash script that looks through error logs and produces a report that prints in a Mac Terminal.

Currently, the output looks like this:

This error report is derived from Command Logs from ________ to __________.

IP addresses:

109.xx.xxx.xxx

Error Codes List: 

(code 12)
(code 30)

Common Errors - Count: 

Code 2: 
Code 10: 
Code 11: 
Code 12: 237
Code 14: 
Code 20: 
Code 23: 
Code 30: 5
Code 35: 
Code 37: 
Code 52: 
/usr/local/bin/backerr: line 45: `$skipping': not a valid identifier
Total: 242

Total Files Transferred: 
3558

Count complete.

The following are details for each error:   
// all of the 242 above-referenced lines //

Skipped files: 
// lists all of the lines that have the word 'skipping\ ' //

As you can see, I do not have the correct identifier:

    /usr/local/bin/backerr: line 45: `$skipping': not a valid identifier

This is the code I have to detect the lines with 'skipping\ ' in them, count the total, and print the total under the Code XX: total above. Also, I want the 'skipping\ ' total to add to 'Total: 242'.

  count=()
  total=0

  while read skipping; do
        (( count[$skipping]++, total++ ))      
  done < <(grep 'skipping\ ' $input_variable)

  for $skipping in $input_variable; do
    echo "Skipped: ${count[$skipping]}"
  done

My expected output of the "Common Errors - Count:" section should be as follows:

    Common Errors - Count: 

    Code 2: 
    Code 10: 
    Code 11: 
    Code 12: 237
    Code 14: 
    Code 20: 
    Code 23: 
    Code 30: 5
    Code 35: 
    Code 37: 
    Code 52: 
    Skipped: 107 (I made up this number for this question)
    Total: 349

I am stuck here. Please help.

As a work-around, instead of using the code below:

      while read skipping; do
            (( count[$skipping]++, total++ ))      
      done < <(grep 'skipping\ ' $input_variable)

      for $skipping in $input_variable; do
        echo "Skipped: ${count[$skipping]}"
      done

I replaced that with:

  echo "Total Skipped Files: " ; egrep -c 'skipping' $input_variable ;

But, this does not really produce the ideal outcome as I originally envisioned.

@SMA: Process substitution: treats the output of a command like a file. — Benjamin W.
– Benjamin W., Commented Jan 6, 2016 at 18:45
Underneath all of the Code totals (Code 2: Code 10: Code 11: Code 12: 237 Code 14: Code 20: Code 23: Code 30: 5 Code 35: Code 37: Code 52:)' I would like to have the a row that says `Skipped: 'n'' where is 'n' is the total. Then, I would like to add the Skipped total to the Total at the bottom. Do you understand? — technerdius
– technerdius, Commented Jan 6, 2016 at 20:23
I just updated the question with the desired output. Thank you. — technerdius
– technerdius, Commented Jan 6, 2016 at 20:58
Hmm but how are you getting 107 and 349 numbers from above input? — anubhava
– anubhava, Commented Jan 6, 2016 at 21:10

chrisaycock · Accepted Answer · 2016-01-06 18:42:55Z

2

Your for loop shouldn't have a dollar sign for the indexing variable:

for skipping in $input_variable; do
   ^^^

answered Jan 6, 2016 at 18:42

chrisaycock

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3 Comments

technerdius Over a year ago

I did that, but I get `/usr/local/bin/script: line 44: filename: syntax error: invalid arithmetic operator (error token is "@filename"'

chrisaycock Over a year ago

@technerdius Where is "filename" in your script?

technerdius Over a year ago

filename is $input_variable

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