Assign checkbox array to variable

Question

I am trying to use a checkbox to populate a single string in a database with specific formatting. I can successfully print the array, but I don't understand how to assign this to a variable in order to connect to the database and to use again elsewhere on the site. Here is the html:

 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="C">Commercials
 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="CP">Commercial Print
 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="V">Voice Overs
 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="X">Background Work
 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="F">Film
 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="TV">Television
 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="BT">Business Theatre Industrials
 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="I">Film Industrials
 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="MV">Music Videos

PHP:

foreach($_POST['bookCodes'] as $codes) {
    print "(".$codes.")";
};

I want the printed string to equal $bookCodes. I have tried putting the array in a function but then I get the first value only. Here is that code:

function prepBookCodes ($value)
{
    if (isset($_POST[$value])) {
        foreach ($_POST[$value] as $codes) {
            return "(" . $codes . ")";
        }
    }
}
$bookCodes = prepBookCodes('bookCodes');

print $bookCodes;

Any help would be greatly appreciated!

aynber · Accepted Answer · 2016-01-08 15:55:39Z

2

Your first declaration doesn't have it as an array:

<input type="checkbox" id="bookCodes" name="bookCodes" value="C">Commercials

Should be

 <input type="checkbox" id="bookCodes" name="bookCodes[]" value="C">Commercials

answered Jan 8, 2016 at 15:55

aynber

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1 Comment

Abigail Hardin Over a year ago

Thanks, I missed that. It still is not working though. I'm getting the same result from PHP segments.

Daniel PurPur · Accepted Answer · 2016-01-11 16:44:34Z

1

Concatenation is the answer. Make your function return something please!

function prepBookCodes ($value)
{
    if (isset($_POST[$value])) {
        foreach ($_POST[$value] as $codes) {
            $string .= "(" . $codes . ")";
        }
    }

    return $string;
}
$bookCodes = prepBookCodes('bookCodes');

edited Jan 11, 2016 at 16:44

answered Jan 8, 2016 at 16:19

Daniel PurPur

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Comments

Ken Carvajal · Accepted Answer · 2016-01-08 16:03:31Z

0

function prepBookCodes ($value)
{
    if (isset($_POST[$value])) {
        foreach ($_POST[$value] as $codes) {
           echo "(" . $codes . ")";
        }
    }
}

answered Jan 8, 2016 at 16:03

Ken Carvajal

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Comments

The fourth bird · Accepted Answer · 2016-01-08 16:16:09Z

0

Maybe you can concatenate the post values into a single variable $bookCodes:

if ($_SERVER['REQUEST_METHOD'] === 'POST') {
    if (isset($_POST['bookCodes'])) {
        $bookCodes = '';
        foreach ($_POST['bookCodes'] as $codes) {
            $bookCodes .= "(" . $codes . ")";
        }
        print $bookCodes;
    }
}

If you for example check all the checkboxes, the $bookCodes variable will contain:

(C)(CP)(V)(X)(F)(TV)(BT)(I)(MV)

answered Jan 8, 2016 at 16:16

The fourth bird

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