How to do PHP array_intersect by keys not by values?

Question

$master = ['111' => 'foo', '124' => 'bar', '133' => 'baz'];

$check = ['111' => 14, '133' => 23 ]';

I want to remove all keys from $master that do not exists in $check. So the result in this example should be:

$newMaster = ['111' => 'foo', '133' => 'baz'];

Any idea how to do this ? Thanks in advance.

array_intersect by keys <- remove 3 characters (excluding spaces :) and add an underscore to it, and you have your answer: array_intersect_key — Rizier123
– Rizier123, Commented Jan 11, 2016 at 12:14
Partial dupe: stackoverflow.com/q/11644267/3933332 (Just without the flipping of the second array) — Rizier123
– Rizier123, Commented Jan 11, 2016 at 12:16
@Havelock I excluded the spaces, so by and the s from keys = 3 ;) — Rizier123
– Rizier123, Commented Jan 11, 2016 at 12:17

Havelock · Accepted Answer · 2016-01-11 12:15:28Z

4

Yes, simply use array_intersect_key()

$newMaster = array_intersect_key($master, $check);

answered Jan 11, 2016 at 12:15

Havelock

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Waqas Shahid · Accepted Answer · 2016-01-11 12:29:03Z

0

Yeah you can simply use:

var_dump(array_intersect_key($master, $check));

answered Jan 11, 2016 at 12:29

Waqas Shahid

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jilesh · Accepted Answer · 2016-01-11 12:33:34Z

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$master = ['111' => 'foo', '124' => 'bar', '133' => 'baz'];

$check = ['111' => 14, '133' => 23 ];


$intersectArray = array_intersect_key($master, $check);

Here key will compare using array_intersect_key() function it will compare your $check key in $master and give you result where $check key is matched in $master and you got output ['111' => 'foo', '133' => 'baz']; in $intersectArray

For more details you will check this link http://php.net/manual/en/function.array-intersect-key.php

answered Jan 11, 2016 at 12:33

jilesh

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