How can I pass a variable and a string into the same jQuery selector?

Question

I have the following:

var x = '.'+this.id;

and this does not work:

$(x,'#thumb').show();

but this does:

$(x).show();

and obviously so does this:

$('#thumb').show();

What am I missing? Should I be doing something else in general to pass variables (even on their own) through jQuery?

Well, $(x + '#thumbs').show() doesn't work. $(x+', #thumbs').show() works fine. But it looks so sloppy. — Isaac Lubow
– Isaac Lubow, Commented Aug 13, 2010 at 4:45
Too bad jquery can't read minds, why didn't creators think of that? :) — Nikita Rybak
– Nikita Rybak, Commented Aug 13, 2010 at 4:46

Jeevan Takhar · Accepted Answer · 2010-08-13 04:41:12Z

2

You need to concatenate the two strings together:

$(x+',#thumb').show();

answered Aug 13, 2010 at 4:41

Jeevan Takhar

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