PHP: Issue decoding JSON array

Question

I'm attempting to decode a JSON array, however I get the following error:

Object of class stdClass could not be converted to string

The JSON Encoded array is shown below:

echo json_decode('{
     "type": "FeatureCollection",
     "features": [
      {
       "type": "Feature",
       "geometry": {
        "type": "Point",
        "coordinates": [
         149.23531999999997,
         -35.352484
        ]
       },
       "properties": {
        "Fcilty_typ": "MO",
        "gx_id": "1"
       }
      }
     ]
    }'
);

I've stripped some fields out of this to keep it more compact for this query. Could anyone suggest what the issue is here?

Thanks

answer is already in question.. json_decode will return object no a string — Chetan Ameta
– Chetan Ameta, Commented Jan 13, 2016 at 12:24

Daan · Accepted Answer · 2016-01-13 12:24:39Z

2

You can't echo the JSON you decoded (which is an object), you can however try a var_dump:

var_dump(json_decode('{
     "type": "FeatureCollection",
     "features": [
      {
       "type": "Feature",
       "geometry": {
        "type": "Point",
        "coordinates": [
         149.23531999999997,
         -35.352484
        ]
       },
       "properties": {
        "Fcilty_typ": "MO",
        "gx_id": "1"
       }
      }
     ]
    }'
));

answered Jan 13, 2016 at 12:24

Daan

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Comments

RiggsFolly · Accepted Answer · 2016-01-13 12:35:03Z

In JSON,

The { character denotes the start of an object.

The [ character denotes the start of an array.

So when you do a json_decode() it takes a string and makes out of it whatever the json structure denotes. Therefore in your case it creates an PHP Object of type stdClass with properties etc

You cannot echo an object, but you can use these functions on both Arrays and Objects

print_r() a nice simple display of the data

var_dump() a more complex to read display of the data in my opinion
           but it does show data types and sizes

var_export() similiar to print_r()

You can also add a second paameter to the json_decode($string, true) and it will convert objects found in the json string representaion of the data structure to Arrays, although I have never seen the need for this.

Vitor Villar · Accepted Answer · 2016-01-13 12:24:44Z

0

You are trying to echo a class, and the echo just print string.

Try change the echo for var_dump.

var_dump will show you the classes properties.

answered Jan 13, 2016 at 12:24

Vitor Villar

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Comments

nullexception · Accepted Answer · 2016-01-13 12:25:40Z

0

You are decoding JSON data and echoing it out. Dont forget that echoing only works for strings, the JSON decode returns an other object.

answered Jan 13, 2016 at 12:25

nullexception

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