Get the last array index after a foreach loop

Question

Hi I'm trying to find the last array of $linkNumber from my for each loop as i have an image outside the foreach loop that needs the data-slide-index to be the last array plus 1. Any help how to achieve this?

<?php $linkNumber = 0;?>  

<?php foreach ($variables as $variable){ ?>
     <img src="$variable" data-slide-index="$linkNumber++"/>
<?php } ?>
<img src="#" data-slide-index="<?php $linkNumber + 1;?>"

use array_pop() function of php as this will get last element of array.. — Abbas
– Abbas, Commented Jan 14, 2016 at 11:54

worldofjr · Accepted Answer · 2016-01-14 11:59:14Z

1

If we ignore that your variables won't be printed or evaluated at all for the moment; essentially what you are doing is correct. Your problem is most of your logic isn't being executed.

You need to explicitly echo variables and evaluations should be inside a PHP block, as follows

<?php
$linkNumber = 0;

foreach ($variables as $variable) :
    ?>
    <img src="<?= $variable; ?>" data-slide-index="<?= $linkNumber; ?>"/>
    <?php
    $linkNumber++;
endforeach;
?>

<img src="#" data-slide-index="<?= $linkNumber; ?>"

answered Jan 14, 2016 at 11:59

worldofjr

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1 Comment

BritishSam Over a year ago

Thank you, i'm an idiot, i had my echo in the foreach but missed it in the one outside it ha

BenB · Accepted Answer · 2016-01-14 12:04:54Z

1

This should work:

<?php $linkNumber = 0;?>  

<?php foreach ($variables as $variable){ ?>
 <img src="$variable" data-slide-index="$linkNumber++"/>
 <?php } ?>
 <img src="#" data-slide-index="<?php echo count($variables) + 1;?>"

answered Jan 14, 2016 at 12:04

BenB

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1 Comment

worldofjr Over a year ago

<img src="$variable" data-slide-index="$linkNumber++"/> will not evalutate.

Alex · Accepted Answer · 2016-01-14 12:05:06Z

1

Your code seems to work except for some syntax issues. Eliminating these this code works for me:

<?php
$linkNumber = 0;

$variables = array("test", "test2");

foreach ($variables as $variable){
     echo '<img src="' . $variable . '" data-slide-index="' . $linkNumber++ . '"/>' . "\n";
}
echo '<img src="#" data-slide-index="' . $linkNumber . '">';

?>

http://ideone.com/01cWNg

answered Jan 14, 2016 at 12:05

Alex

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