PHP dynamic class name laravel

Question

I am using Laravel and having trouble creating a class with a string. The class is in the same name space of the class calling it.

The below code fails on the third line, I am unsure what I am doing wrong.

$class= "Variant";
$s = new Variant();
$nc = new $class();

Try adding the full namespace to the string class and see if it works like: "\\Foo\\Bar\\Variant". — Rainner
– Rainner, Commented Jan 14, 2016 at 14:36
@rainer I had tried several different combinations, but this works (SplitTest) is my namespace of the class $class = "\\SplitTest\\Variant" — Charles Bryant
– Charles Bryant, Commented Jan 14, 2016 at 14:45
Possible duplicate of Laravel 5.1: Calling a function from string — lagbox
– lagbox, Commented Jan 14, 2016 at 14:47
Possible duplicate of PHP: Instantiating a class from a variable oddly fails — Havenard
– Havenard, Commented Jan 14, 2016 at 14:54

Charles Bryant · Accepted Answer · 2016-01-14 14:56:08Z

3

Ok the answer to this is I needed a namespace on the class.

In composer.json

"psr-4": {
    "SplitTest\\": "app/library/SplitTest/"
}

Then called the class as so:

$class= "//SplitTest//Variant";
$s = new Variant();
$nc = new $class();

If you to the psr-4 definition you will need to run

php artisan dump-auto

answered Jan 14, 2016 at 14:56

Charles Bryant

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Comments

aphodius · Accepted Answer · 2016-01-14 14:43:47Z

1

This is actually what namespaces are for:

$s = new \OneNamespaceName\Variant();

This is often used in a Factory pattern. So namespaces are per-file so you need to include this in the the class declaration for Variant.

answered Jan 14, 2016 at 14:43

aphodius

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