Converting Ruby to Python

Question

I'm trying to convert my ruby script to python. I'm not very familiar with python so I am getting a TypeError.

printer.rb

Lease = Struct.new(:property, :renter)
lease_list = []

File.open('input.txt').readlines.each do |line|
  p, r = line.split(' - ')
  lease_list << Lease.new(p.tr('#', ''), r)
end

# sort by decimal value
lease_list.sort_by { |m| m.property.scan(/\d+/)[0].to_i }.each do |lease|
  puts "\##{lease.property} - #{lease.renter}"
end

printer.py

import re

class Lease:
  def __init__(self, renter=None, unit=None):
    self.renter = renter
    self.property = unit

lease_list = []
import sys
lines = open('input.txt', 'r')
for line in lines:
    l, m = line.split(' - ')
    lease_list.append(Lease(l,m))
lines.close()

print lease_list.sort(key=lambda lease: re.split(r"\d+", lease.property))

python error

Traceback (most recent call last):   File "printer.py", line 16, in
<module>
    print lease_list.sort(key=lambda str: re.split(r"\d+", str))   File "printer.py", line 16, in <lambda>
    print lease_list.sort(key=lambda str: re.split(r"\d+", str))   File
"/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/re.py",
line 171, in split
    return _compile(pattern, flags).split(string, maxsplit) TypeError: expected string or buffer

That's not a syntax error, it's a TypeError. A syntax error shows up as SyntaxError. And yes, there is a significant difference. — TigerhawkT3
– TigerhawkT3, Commented Jan 21, 2016 at 6:05
@AvinashRaj In the sort I am trying to find the decimal value the unit attribute and sort by that — Antarr Byrd
– Antarr Byrd, Commented Jan 21, 2016 at 6:05
Now that you've changed the code, the error doesn't make sense — Open AI - Opting Out
– Open AI - Opting Out, Commented Jan 21, 2016 at 6:16

Dimitris Fasarakis Hilliard · Accepted Answer · 2016-01-21 11:31:19Z

3

The problem is here:

print lease_list.sort(key=lambda str: re.split(r"\d+", str))

The str name [edit: see Question edit history], which you generally shouldn't use as a name, even as throwaways) which is assigned values contained in your list and consequently passed to re.split() is an object of type Lease:

lease_list.append(Lease(l,m))

This isn't accepted as an argument to re.split it likes munching on strs. hence the TypeError. Lease has two attributes which are strs after the line.split(' - '):

self.renter = renter
self.property = unit

Use one of these in re.split() (whichever is required for your use-case) with:

print lease_list.sort(key=lambda obj: re.split(r"\d+", obj.renter))

or:

print lease_list.sort(key=lambda obj: re.split(r"\d+", obj.property))

Forgot to mention, sorting a list with list.sort will return None since it sorts the list in place, printing the value here has no use.

edited Jan 21, 2016 at 11:31

answered Jan 21, 2016 at 6:04

Dimitris Fasarakis Hilliard

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2 Comments

Antarr Byrd Over a year ago

It prints out None

Dimitris Fasarakis Hilliard Over a year ago

Ah yes, sort sorts in place, returning None. The list you passed in is sorted, though.

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