Convert Array to JSON string php

Question

I have an array like this

$prebook=array(
             'sourceCity'=>$_POST['source'], 
             'destinationCity'=>$_POST['dest'],
             'doj'=>$_POST['doj'],
             'routeScheduleId'=>$_POST['routeid'],
              'boardingPoint'=>array(
                  'id'=>$id,
                  'location'=>$location,
                  'time'=>$time
              ),     
              'customerName'=>$_POST['fname'],
              'customerLastName'=>$_POST['lname'],
              'customerEmail'=>$_POST['email'],
              'customerPhone'=>$_POST['mobileno'],
              'emergencyPhNumber'=>$_POST['emc-number'],
              'customerAddress'=>$_POST['address'],
              'blockSeatPaxDetails'=>array(array(
                  'age'=>$_POST['age'][$key],
                  'name'=>$value,
                  'seatNbr'=>$_POST['seat-no'][$key],
                  'Sex'=>$_POST['gender'.$no],
                  'fare'=>$_POST['base-fare'][$key],
                  'totalFareWithTaxes'=>$_POST['amount'][$key],
                  'ladiesSeat'=>$ladies,
                  'lastName'=>$_POST['plname'][$key],
                  'mobile'=>$_POST['mobileno'],
                  'title'=>'Mr',
                  'email'=>$_POST['email'],
                  'idType'=>$_POST['idtype'],
                  'idNumber'=>$_POST['id-number'],
                  'nameOnId'=>$value,
                  'primary'=>true,
                  'ac'=>$ac,
                  'sleeper'=>$sleeper
         )),
                'inventoryType'=>$_POST['invtype']             
           )

From this i want to get Json string look like this

apiBlockTicketRequest:{"sourceCity":"Hyderabad","destinationCity":"Bangalore","doj":"2016-01-22","routeScheduleId":"6717","boardingPoint":{"id":"2889","location":"Mettuguda,Opp. Mettuguda Church","time":"04:50PM"},"customerName":"jj","customerLastName":"jjj","customerEmail":"[email protected]","customerPhone":"7779","emergencyPhNumber":"7878","customerAddress":"gjgj","blockSeatPaxDetails":[{"age":"22","name":"hjhj","seatNbr":"G4","Sex":"F","fare":"900","totalFareWithTaxes":"945","ladiesSeat":false,"lastName":"hjhj","mobile":"7779","title":"Mr","email":"[email protected]","idType":"Aadhar Card","idNumber":"jkjk","nameOnId":"hjhj","primary":true,"ac":false,"sleeper":false}],"inventoryType":"0"}

Here is my code

$data =json_encode($prebook);
$json='apiBlockTicketRequest:'.$data;
echo $json;

But when i Validate the JSON string using this I will get the following error

Expecting object or array, not string.[Code 1, Structure 1]

Error:Strings should be wrapped in double quotes.

$json='{apiBlockTicketRequest:'.$data.'}'; should be better. Even though writing your own JSON is generally a bad idea. Just let json_encode do all the work. — Rein
– Rein, Commented Jan 22, 2016 at 9:08

Robert · Accepted Answer · 2016-01-22 09:10:08Z

19

You creating invalid json by adding apiBlockTicketRequest to output

 $json='apiBlockTicketRequest'.$data;

instead you can do

$json = json_encode(['apiBlockTicketRequest' => $prebook]);

answered Jan 22, 2016 at 9:10

Robert

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4 Comments

Robert Over a year ago

also if you have php < 5.4 then use array() instead of []

Blessan Kurien Over a year ago

But i don't want { at the begening and end of the string,bcz this json is request of an api service,when i passw this json i wlll get an error from api,

Hanky Panky Over a year ago

Sorry but then don't use that service because it is asking you to produce invalid JSON

Robert Over a year ago

It is required to use { at the begginging so you asking about something that is pseudo json not JSON as @Hanky웃Panky mentioned

Athul Nath · Accepted Answer · 2018-02-26 06:43:41Z

0

Your code is correct to make that string but the entire output string ($json) will never parse as json, only the $data you encoded.

edited Feb 26, 2018 at 6:43

Athul Nath

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answered Feb 26, 2018 at 6:23

zilth

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