Pass promise to another function in Javascript

Question

I would like to do something like this

function doSomething(aPromise) {
    if (/*xxx*/) {
        // doSomethingElse
    } else {
        return aPromise
            .then(doSomethingMore)
    }
}

However, if i do this, aPromise will always be executed when calling doSomething. How do i lazy execute it until it get called

guest271314 · Accepted Answer · 2016-01-23 03:50:42Z

3

Try using aPromise as a function , returning Promise value from calling aPromise() at else block

function aPromise() {
  return Promise.resolve(/* `Promise` return value */)
}

function doSomething(aPromise) {
    if (/*xxx*/) {
        // doSomethingElse
    } else {
        // call `aPromise()` 
        return aPromise()
            .then(doSomethingMore)
    }
}

answered Jan 23, 2016 at 3:50

guest271314

1

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