naming variables from loop jquery

Question

This is a follow question from https://stackoverflow.com/questions/34981100/jquery-loop-to-generate-variables

So i'm trying to make variables in newly created arrays in my function. Then i will have to call each newly created variable to my chart.

var digits = [2012, 01, 5, 88, 2012, 01, 6, 90, 2012, 05, 9, 130];
size = 3;
data = []

while (digits.length > 0)
data.push(digits.splice(0, size));
var mysize = data.length;
for (i = 0; i < data.length; i++) {
  x = 0
  console.log("This is set " + i)
  console.log('This is the data for array ' + i + '\n ' + data[i])
  for (j = 0; j < 3; j++)
  console.log(data[i][j])

MY second console.log statement prints out arrays in sets of four. I need to name each of those arrays, and then i need to be able to call each individual array in my chart, which is in a separate function.

Right now each array is named from the line

console.log('This is the data for array ' + i + '\n ' + data[i])

with no variable set from this line.

The end result should be my1 = [2012,1,5,88] my2 = [2012, 1,6, 90] my3 = [2012, 5, 9, 130] And since the data from my array could scale I wont be able to know how many new variable arrays i need to make. That's why the code should auto generate new array variable names, and break the original data into sets of four.

Then i would have to pass each newly created variable separately into my chart.

This is better start than last question, having some code. Unfortunately still missing critical information.... name them from what? What is expected results structure? — charlietfl
– charlietfl, Commented Jan 25, 2016 at 1:54
Don't use your arrays as associative arrays, you need to convert them to object literals. — zer00ne
– zer00ne, Commented Jan 25, 2016 at 2:33
Ok, but in object literals, how will it auto generate key names? — jumpman8947
– jumpman8947, Commented Jan 25, 2016 at 2:37

Joseph · Accepted Answer · 2016-01-25 01:53:11Z

1

What you need is an object, not an array. Objects have keys which you can use as an identifier.

;(function(){
  'use strict';
  
const CHUNK_SIZE = 3;
let digits       = [2012, 1, 5, 88, 2012, 1, 6, 90, 2012, 5, 9, 130];
let names        = ['foo', 'bar', 'baz'];
let data         = {};

for(let i = 0; digits.length; i++)
  data[names[i]] = digits.splice(0, CHUNK_SIZE);

console.log(data.foo);
console.log(data.bar);
console.log(data.baz);  
  
}());

Also, I notice that some of your numbers start with 0. JS will treat them as octal instead of decimal. Either remove the 0 so they become decimals or if you want to preserve it, make them strings instead.

answered Jan 25, 2016 at 1:53

Joseph

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1 Comment

jumpman8947 Over a year ago

But lets say the lets digits scales from time to time, you wont know how many names you need that why the code should auto generate variables for names.

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