PHP get image src

Question

$variable = '<img src="http://www.gravatar.com/avatar/66ce1f26a725b2e063d128457c20eda1?s=32&d=identicon&r=PG" height="32" width="32" alt=""/>';

How to get src of this image?

Like:

$src = 'http://www.gravatar.com/avatar/66ce1f26a725b2e063d128457c20eda1?s=32&d=identicon&r=PG';

Thanks.

Is there anything else in $variable, e.g. other HTML or just the string? — Gordon
– Gordon, Commented Aug 18, 2010 at 9:15

Piotr Müller · Accepted Answer · 2010-08-18 09:17:06Z

6

use regex

preg_match( '@src="([^"]+)"@' , $variable , $match );

And src will be in $match, see print_r( $match ). But this is only for this situation, if you want universal solution (like ' against " etc.) use html/DOM parser.

answered Aug 18, 2010 at 9:17

Piotr Müller

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1 Comment

Gordon Over a year ago

Actually one of the rare cases where I think a Regex is justified and better suited than a full blown HTML parser for getting to the desired outcome.

greg0ire · Accepted Answer · 2010-08-18 09:17:00Z

4

You can use an html parser for this. See this one: http://simplehtmldom.sourceforge.net/ (I hope this works for nodes, not just for entire pages).

answered Aug 18, 2010 at 9:17

greg0ire

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1 Comment

Gordon Over a year ago

Suggested third party alternatives that actually use DOM instead of String Parsing: phpQuery, Zend_Dom, QueryPath and FluentDom. However, for the OP's UseCase, a HTML/DOM Parser might be overkill.

Naveed · Accepted Answer · 2010-08-18 09:49:09Z

1

Use HTML DOM. Download and include simple_html_dom.php file in your script.

Then get image URLs like this:

$html = str_get_html('<img src="http://www.gravatar.com/avatar/66ce1f26a725b2e063d128457c20eda1?s=32&d=identicon&r=PG" height="32" width="32" alt=""/>');

// Find all images
foreach($html->find('img') as $element)
       echo $element->src . '<br>';

edited Aug 18, 2010 at 9:49

answered Aug 18, 2010 at 9:43

Naveed

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