Powershell copy-item, store new folder as variable

Question

I am trying to create a simple script to move a directory to a secured location on our servers. I want to pull the new file location as a variable to include in an email that I have labeled $secure. Any help would be appreciated - Thanks!

Write-Host "Enter Package Location: " -NoNewLine -ForegroundColor Green
$package = Read-Host
Copy-Item -Path $package -Destination "C:\PS" -Force -Recurse
$secure = ???

Mathias R. Jessen · Accepted Answer · 2016-02-02 19:20:56Z

1

Use the -PassThru parameter with Copy-Item:

$secure = Copy-Item -Path $package -Destination "C:\PS" -Force -Recurse -PassThru

to get the copied item(s)

To just get the new root directory (ie. "C:\PS\packagedir"), use Split-Path -Leaf to grab the folder name from $package and combine with the destination path using Join-Path:

Write-Host "Enter Package Location: " -NoNewLine -ForegroundColor Green
$package = Read-Host
$destination = "C:\PS"
Copy-Item -Path $package -Destination $destination -Force -Recurse
$secure = Get-Item (Join-Path $destination -ChildPath (Split-Path $package -Leaf))

edited Feb 2, 2016 at 19:20

answered Feb 2, 2016 at 19:06

Mathias R. Jessen

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2 Comments

Ryan Tice Over a year ago

Thanks! Ideally I would like just the folder structure as the variable, not the contents in these directories though, is there a way to get only that?

Mathias R. Jessen Over a year ago

@RyanTice you bet! Updated the answer

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