PHP array in table using implode()

Question

I'm trying to output these arrays in a 3x4 table. At the moment it only outputs the first value of every array in a new row in a 1 column array. While it should be 3 columns with 'qualitypoint','quality' and 'q' next to eachother. And then in a new row 'technologies' , 'tech' and 't' next to eachother etc.

Output screenshot

<?php 
$Array1 = array('qualitypoint', 'technologies', 'India','Hey');
$Array2 = array('quality', 'tech', 'Ind','He');
$Array3 = array('q', 't', 'I','H');
echo '<table border = "3px">';
echo '<tr><td>' . implode('</tr><tr>', $Array1).'</td></tr>';
echo '<tr><td>' . implode('</tr><tr>', $Array2).'</td></tr>';
echo '<tr><td>' . implode('</tr><tr>', $Array3).'</td></tr>';
echo '</table>';
?>

can you show what is your expected outcome you want? its really confusing what you want? — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Feb 4, 2016 at 16:42

J. Gower · Accepted Answer · 2016-02-04 16:35:57Z

5

implode('</td><td>', $Array1)

implode('</td><td>', $Array2)

implode('</td><td>', $Array3)

Guess this is what you wanted to do... To use td instead of tr

answered Feb 4, 2016 at 16:35

J. Gower

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3 Comments

Max Over a year ago

I need a 3x4 table not 4x3, 'qualitypoint','quality' and 'q' should be next to eachother in their own column. Thank you anyways though.

J. Gower Over a year ago

echo '<tr><td>' . $Array1[0] . '</td><td>' . $Array2[0] . '</td><td>' . $Array3[0] . '</td></tr>'; echo '<tr><td>' . $Array1[1] . '</td><td>' . $Array2[1] . '</td><td>' . $Array3[1] . '</td></tr>'; echo '<tr><td>' . $Array1[2] . '</td><td>' . $Array2[2] . '</td><td>' . $Array3[2] . '</td></tr>'; So this is what you need? You can write that with loops ofc...

Max Over a year ago

Hanky got what I needed, thank you very much for your help anyways!

Werner · Accepted Answer · 2016-02-04 16:52:04Z

2

If you want you can also leave the arrays as they are. But the implode cannot be used that way. This will also work for you:

$Array1 = array('qualitypoint', 'technologies', 'India','Hey');
$Array2 = array('quality', 'tech', 'Ind','He');
$Array3 = array('q', 't', 'I','H');

echo '<table border = "3px">';
foreach($Array1 as $key => $value){
echo '<tr><td>' . $Array1[$key] .'</td><td>' . $Array2[$key] .'</td><td>' . $Array3[$key] .'</td></tr>';
}
echo '</table>';

answered Feb 4, 2016 at 16:52

Werner

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1 Comment

Max Over a year ago

This worked how i wanted it, thank you very much for the help!

Hanky Panky · Accepted Answer · 2016-02-04 17:02:02Z

1

Forget all that implode mess that will break on the first possible chance. First restructure your arrays and merge them into 1 array.

$Array[1] = array('qualitypoint', 'technologies', 'India','Hey');
$Array[2] = array('quality', 'tech', 'Ind','He');
$Array[3] = array('q', 't', 'I','H');

Then simply do

echo '<table>';
echo '<table>';
for($i=0;$i<=3;$i++)
{
    echo "<tr>";
    for($j=1;$j<=3;$j++)
    {    
     echo "<td>{$Array[$j][$i]}<td>";
    }
    echo "</tr>";    
}
echo '</table>';

Output

table>
<tr>
    <td>qualitypoint<td>
    <td>quality<td>
    <td>q<td>
</tr>
<tr>
    <td>technologies<td>
    <td>tech<td>
    <td>t<td>
</tr>
<tr>
    <td>India<td>
    <td>Ind<td>
    <td>I<td>
</tr>
<tr>
    <td>Hey<td>
    <td>He<td>
    <td>H<td>
</tr>
</table>

Tip You can use count() and not worry about hardcoding the loop's limit. That way you can scale data as much as you want without changing the code

edited Feb 4, 2016 at 17:02

answered Feb 4, 2016 at 16:48

Hanky Panky

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2 Comments

Max Over a year ago

This worked but was again a 4x3 table not 3x4. Thanks anyways.

Max Over a year ago

Alright thank you very much! Will be using this since it's cleaner and easier to change than Werner's answer. Thank you Hanky Panky!

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