Printing out element of array, it shows hash code instead of value

Question

Below is the class. The static method findMax returns arr[maxIndex] and when I try to print that out in the main method I get a memory location instead of the value. I thought to print out a value at a certain index of an array.

I would like to print the value, but without changing the existing method (so I have to fix the problem via the main).

public class Problem1 
 {
     public static <AnyType extends Comparable<AnyType>> AnyType findMax(AnyType[] arr) 
    {
        int maxIndex = 0;
        for (int i = 1; i < arr.length; i++)
            if ( arr[i].compareTo(arr[maxIndex]) > 0 )
               maxIndex = i;
        return arr[maxIndex];
    }

    public static void main(String[ ] args)
    {
        Rectangle rect1 = new Rectangle(1,2);
        Rectangle rect2 = new Rectangle(2,2);
        Rectangle rect3 = new Rectangle(3,2);
        Rectangle rect4 = new Rectangle(4,2);
        Rectangle rect5 = new Rectangle(5,3);

        Rectangle[ ] rectangles = new Rectangle[5];
        rectangles[0] = rect1;
        rectangles[1] = rect2;
        rectangles[2] = rect3;
        rectangles[3] = rect4;
        rectangles[4] = rect5;

        System.out.println(findMax(rectangles));

    }

}

Presumably you need to Override toString in Rectangle. — Elliott Frisch
– Elliott Frisch, Commented Feb 5, 2016 at 3:58

dave · Accepted Answer · 2016-02-05 04:00:40Z

2

Your findMax() method returns a Rectangle. By default, Java does not know how to print a Rectangle. So you need to override toString() on that class. Currently, the default, Object.toString() is being used, which simply prints the hashcode.

answered Feb 5, 2016 at 4:00

dave

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abdulrafique · Accepted Answer · 2016-02-05 04:09:45Z

0

Override toString method of Rectangle class

answered Feb 5, 2016 at 4:09

abdulrafique

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