PHP converting an image to a binary file test

Question

I wanted to try to convert an image to Binary.

I found a script online but it does not work.

Could someone please advise why?

<?php

$image="image003.jpg";

$data = fopen ($image, 'rb');
$size=filesize ($image);
$contents= fread ($fd, $size);
fclose ($fd);

$encoded= base64_encode($contents);

echo $encoded;

 ?>

I have an error come up on line 8 and 9

Warning: fread() expects parameter 1 to be resource

and

Warning: fclose() expects parameter 1 to be resource,

$fd isn't defined here. Please show the code where $fd is defined. — Richard Theobald
– Richard Theobald, Commented Feb 5, 2016 at 5:34
@RichardTheobald Thats the entire code. I found it online and thats the entire script included — Renegade Rob
– Renegade Rob, Commented Feb 5, 2016 at 5:35
I think you need to use $data and not $fd. Since you stored the file in $data — Architect Nate
– Architect Nate, Commented Feb 5, 2016 at 5:38

Samir Selia · Accepted Answer · 2016-02-05 05:35:49Z

9

Use $data instead of $fd

$data = fopen ($image, 'rb');
$size=filesize ($image);
$contents= fread ($data, $size);
fclose ($data);

answered Feb 5, 2016 at 5:35

Samir Selia

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borracciaBlu · Accepted Answer · 2016-02-05 05:39:56Z

2

As you can see here http://php.net/manual/en/function.fread.php.
So as you can read fread need a resource generate with fopen.

In your case:

<?php

$image = "image003.jpg"; // be careful that the path is correct

$data = fopen($image, 'rb');
$size = filesize($image);
$contents = fread($data, $size);
fclose($data);

$encoded = base64_encode($contents);

echo $encoded;

?>

edited Feb 5, 2016 at 5:39

answered Feb 5, 2016 at 5:36

borracciaBlu

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2 Comments

Richard Theobald Over a year ago

This will not work for the same reason his original code doesn't work; $fd is undefined. ;-)

borracciaBlu Over a year ago

@RichardTheobald you right i missed the handler in fclose.. i was focus on fread, Thaks ;)

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