Running script with arguments through ansible

Question

[Ansible version == 2.1.0]

In order to run a script which is present locally on the target server, we can use Ansible's "command" module. Following can be done easily:

- name: Executing getpkgs.sh to download packages.
  command: sh "/path/to /dir/scriptName.sh" arg1 arg2 arg3 arg4

I have my script names and the arguments stored in ansible variables. For example, the following variable contains all the script names and the arguments to be passed to those scripts:

scripts_to_execute:
  - { filename: "/path/to/file/file1.sh", args: "arg11 arg12 arg13"}
  - { filename: "/path/to/file/file2.sh", args: "arg21 arg22"}
  - { filename: "/path/to/file/file3.sh", args: "arg31 arg32 arg33 arg34"}

And i want all these files which are already present on the target server, to be executed using with_items. Trying to achieve something like the following:

- name: Executing all files.
  command: sh "{{item.filename}}" "{{item.args}}"
  with_items: scripts_to_execute

I am trying to pass the script name followed by the string containing all arguments that are to be passed into the script. But it is considering that string of arguments as a single argument.

@udondan, The syntax error was due to some other issue, I corrected it. Edited the question. I am trying to pass multiple arguments but it is considering that string as single argument. Please help; — Shasha99
– Shasha99, Commented Feb 8, 2016 at 5:53

udondan · Accepted Answer · 2016-02-08 05:55:58Z

6

But it is considering that string of arguments as a single argument.

I think that makes sense since you pass the args in quotes. Did you try without quotes?

- name: Executing all files.
  command: sh "{{item.filename}}" {{item.args}}
  with_items: scripts_to_execute

answered Feb 8, 2016 at 5:55

udondan

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