PHP preg_replace only numbers

Question

I have a string and I want to get only number witch is between 5 and 7 charts. Here my problem:

$string = "Test 1 97779 test";
if(strlen(preg_replace("/[^0-9]/", "", $string)) >= 5 && strlen(preg_replace("/[^0-9]/", "", $parts[7])) <= 7) {
    $var = preg_replace("/[^\d-]+/", "", $string);
}

Result is: 19779, but I want only 97779. If someone have any suggestion I will be very glad. Thanks in advance.

bobble bubble · Accepted Answer · 2016-02-05 15:42:54Z

3

Your friend is preg_match

if(preg_match('/\b\d{5,7}\b/', $str, $out))
  $var = $out[0];

\b matches a word boundary
\d{5,7} in between 5 to 7 digits \d

See demo at eval.in

answered Feb 5, 2016 at 15:42

bobble bubble

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5 Comments

diank Over a year ago

God bless you, I will send you beer! Thank you, you are great! :)

diank Over a year ago

one little question how I can get if $string = "Tes97779 test";

bobble bubble Over a year ago

@diank In this case use lookarounds: /(?<!\d)\d{5,7}(?!\d)/ like in this demo at regex101. This one matches 5 to 7 digits not bordering at another digit.

bobble bubble Over a year ago

@diank If you want to cut off the first ten, just remove the lookahead part (?!\d)

bobble bubble Over a year ago

@diank Yer welcome! Also see the regex faq if interested.

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