PHP - Checking for empty element in 2D array

Question

I have an array which looks like the following

array:2 [▼
  0 => array:1 [▼
    "input1" => "Something"
  ]
  1 => array:1 [▼
    "input2" => ""
  ]
]

Now the first element will always have some data. It is the second element I am interested in. At the moment, I am trying this

if(!empty($clientGroup[0][1]) || !empty($clientGroup[1][1]))
    var_dump("Some Data");
} else {
    var_dump("Both Empty");
}

The else should only be triggered if both elements are empty e.g.

array:2 [▼
  0 => array:1 [▼
    "input1" => ""
  ]
  1 => array:1 [▼
    "input2" => ""
  ]
]

If one of them have any data, the if should be triggered (so for the first array I showed, the if should be triggered).

How would I go about doing this, empty does not seem to work.

Thanks

What is going wrong? Does your first array generate "Some Data" or "Both Empty"? — showdev
– showdev, Commented Feb 5, 2016 at 17:18
Based on the answer you accepted, I assume you were always getting "Both Empty". — showdev
– showdev, Commented Feb 5, 2016 at 17:33

Steve · Accepted Answer · 2016-02-05 17:15:45Z

2

The 2nd level keys do not exist so you will always be told the values are empty. Change the line

if(!empty($clientGroup[0][1]) || !empty($clientGroup[1][1]))

to,

if(!empty($clientGroup[0]['input1']) || !empty($clientGroup[1]['input2']))

and you should get the results you're after.

answered Feb 5, 2016 at 17:15

Steve

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Comments

C.Rouillon · Accepted Answer · 2016-02-05 17:27:46Z

1

It's not realy 2D array because you have associative array inside an other array.

you must use key name (input1, input2) to access the value.

I recommend to use

if($retourdata[0]["input1"] !== "" || $retourdata[1]["input2"] !== "")

answered Feb 5, 2016 at 17:27

C.Rouillon

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