Java - BitSet to integer

Question

So taking the answer with the most upvotes as a base I tried to create a BitSet and set its bits to form the number 478 (111011110) so I did the following:

BitSet set = new BitSet();
set.set(0, true);
set.set(1, true);
set.set(2, true);
set.set(3, false);
set.set(4, true);
set.set(5, true);
set.set(6, true);
set.set(7, true);
set.set(8, false);
System.out.println(bitSetToInt(set));

with the aid of the following method:

public static int bitSetToInt(BitSet bitSet) {
        int bitInteger = 0;

        for (int i = 0; i < 32; i++){
            if (bitSet.get(i)) {
                bitInteger |= (1 << i);
            }
        }
        return bitInteger;
    }

So although I was expecting to get 478 back from this call I am getting 247. Can someone explain me what is going on?

khelwood · Accepted Answer · 2016-02-06 19:38:58Z

1

Bit 0 is the smallest bit (1<<0). You have turned on bits 0, 1, 2, 4, 5, 6 and 7. So your number is 011110111, which is 247.

edited Feb 6, 2016 at 19:38

answered Feb 6, 2016 at 19:36

khelwood

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1 Comment

Rakim Over a year ago

right.. I thought of it but when tried it out I forgot the first index 0 so still got the wrong answer. my bad. thanks

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