How to avoid duplicate columns after join?

The simple answer (from the Databricks FAQ on this matter) is to perform the join where the joined columns are expressed as an array of strings (or one string) instead of a predicate.

Below is an example adapted from the Databricks FAQ but with two join columns in order to answer the original poster's question.

Here is the left dataframe:

val llist = Seq(("bob", "b", "2015-01-13", 4), ("alice", "a", "2015-04-23",10))

val left = llist.toDF("firstname","lastname","date","duration")

left.show()

/*
+---------+--------+----------+--------+
|firstname|lastname|      date|duration|
+---------+--------+----------+--------+
|      bob|       b|2015-01-13|       4|
|    alice|       a|2015-04-23|      10|
+---------+--------+----------+--------+
*/

Here is the right dataframe:

val right = Seq(("alice", "a", 100),("bob", "b", 23)).toDF("firstname","lastname","upload")

right.show()

/*
+---------+--------+------+
|firstname|lastname|upload|
+---------+--------+------+
|    alice|       a|   100|
|      bob|       b|    23|
+---------+--------+------+
*/

Here is an incorrect solution, where the join columns are defined as the predicate left("firstname")===right("firstname") && left("lastname")===right("lastname").

The incorrect result is that the firstname and lastname columns are duplicated in the joined data frame:

left.join(right, left("firstname")===right("firstname") &&
                 left("lastname")===right("lastname")).show

/*
+---------+--------+----------+--------+---------+--------+------+
|firstname|lastname|      date|duration|firstname|lastname|upload|
+---------+--------+----------+--------+---------+--------+------+
|      bob|       b|2015-01-13|       4|      bob|       b|    23|
|    alice|       a|2015-04-23|      10|    alice|       a|   100|
+---------+--------+----------+--------+---------+--------+------+
*/

The correct solution is to define the join columns as an array of strings Seq("firstname", "lastname"). The output data frame does not have duplicated columns:

left.join(right, Seq("firstname", "lastname")).show

/*
+---------+--------+----------+--------+------+
|firstname|lastname|      date|duration|upload|
+---------+--------+----------+--------+------+
|      bob|       b|2015-01-13|       4|    23|
|    alice|       a|2015-04-23|      10|   100|
+---------+--------+----------+--------+------+
*/

This is an expected behavior. DataFrame.join method is equivalent to SQL join like this

SELECT * FROM a JOIN b ON joinExprs

If you want to ignore duplicate columns just drop them or select columns of interest afterwards. If you want to disambiguate you can use access these using parent DataFrames:

val a: DataFrame = ???
val b: DataFrame = ???
val joinExprs: Column = ???

a.join(b, joinExprs).select(a("id"), b("foo"))
// drop equivalent 
a.alias("a").join(b.alias("b"), joinExprs).drop(b("id")).drop(a("foo"))

or use aliases:

// As for now aliases don't work with drop
a.alias("a").join(b.alias("b"), joinExprs).select($"a.id", $"b.foo")

For equi-joins there exist a special shortcut syntax which takes either a sequence of strings:

val usingColumns: Seq[String] = ???

a.join(b, usingColumns)

or as single string

val usingColumn: String = ???

a.join(b, usingColumn)

which keep only one copy of columns used in a join condition.

I have been stuck with this for a while, and only recently I came up with a solution what is quite easy.

Say a is

scala> val a  = Seq(("a", 1), ("b", 2)).toDF("key", "vala")
a: org.apache.spark.sql.DataFrame = [key: string, vala: int]

scala> a.show
+---+----+
|key|vala|
+---+----+
|  a|   1|
|  b|   2|
+---+----+
and 
scala> val b  = Seq(("a", 1)).toDF("key", "valb")
b: org.apache.spark.sql.DataFrame = [key: string, valb: int]

scala> b.show
+---+----+
|key|valb|
+---+----+
|  a|   1|
+---+----+

and I can do this to select only the value in dataframe a:

scala> a.join(b, a("key") === b("key"), "left").select(a.columns.map(a(_)) : _*).show
+---+----+
|key|vala|
+---+----+
|  a|   1|
|  b|   2|
+---+----+

You can simply use this

df1.join(df2, Seq("ts","id"),"TYPE-OF-JOIN")

Here TYPE-OF-JOIN can be

• left
• right
• inner
• fullouter

For example, I have two dataframes like this:

// df1
word   count1
w1     10   
w2     15  
w3     20

// df2
word   count2
w1     100   
w2     150  
w5     200

If you do fullouter join then the result looks like this

df1.join(df2, Seq("word"),"fullouter").show()

word   count1  count2
w1     10      100
w2     15      150
w3     20      null
w5     null    200

try this,

val df_combined = df1.join(df2, df1("ts") === df2("ts") && df1("id") === df2("id")).drop(df2("ts")).drop(df2("id"))

This is a normal behavior from SQL, what I am doing for this:

• Drop or Rename source columns
• Do the join
• Drop renamed column if any

Here I am replacing "fullname" column:

Some code in Java:

this
    .sqlContext
    .read()
    .parquet(String.format("hdfs:///user/blablacar/data/year=%d/month=%d/day=%d", year, month, day))
    .drop("fullname")
    .registerTempTable("data_original");

this
    .sqlContext
    .read()
    .parquet(String.format("hdfs:///user/blablacar/data_v2/year=%d/month=%d/day=%d", year, month, day))
    .registerTempTable("data_v2");

 this
    .sqlContext
    .sql(etlQuery)
    .repartition(1)
    .write()
    .mode(SaveMode.Overwrite)
    .parquet(outputPath);

Where the query is:

SELECT
    d.*,
   concat_ws('_', product_name, product_module, name) AS fullname
FROM
    {table_source} d
LEFT OUTER JOIN
    {table_updates} u ON u.id = d.id

This is something you can do only with Spark I believe (drop column from list), very very helpful!

If anyone is using spark-SQL and wants to achieve the same thing then you can use USING clause in join query.

val spark = SparkSession.builder().master("local[*]").getOrCreate()
spark.sparkContext.setLogLevel("ERROR")
import spark.implicits._

val df1 = List((1, 4, 3), (5, 2, 4), (7, 4, 5)).toDF("c1", "c2", "C3")
val df2 = List((1, 4, 3), (5, 2, 4), (7, 4, 10)).toDF("c1", "c2", "C4")

df1.createOrReplaceTempView("table1")
df2.createOrReplaceTempView("table2")

spark.sql("select * from table1  inner join  table2  using (c1, c2)").show(false)

/*
+---+---+---+---+
|c1 |c2 |C3 |C4 |
+---+---+---+---+
|1  |4  |3  |3  |
|5  |2  |4  |4  |
|7  |4  |5  |10 |
+---+---+---+---+
*/

Inner Join is default join in spark, Below is simple syntax for it.

leftDF.join(rightDF,"Common Col Nam")

For Other join you can follow the below syntax

leftDF.join(rightDF,Seq("Common Columns comma seperated","join type")

If columns Name are not common then

leftDF.join(rightDF,leftDF.col("x")===rightDF.col("y),"join type")

Best practice is to make column name different in both the DF before joining them and drop accordingly.

df1.columns =[id, age, income]
df2.column=[id, age_group]

df1.join(df2, on=df1.id== df2.id,how='inner').write.saveAsTable('table_name')

will return an error while error for duplicate columns

Try this instead try this:

df2_id_renamed = df2.withColumnRenamed('id','id_2')
df1.join(df2_id_renamed, on=df1.id== df2_id_renamed.id_2,how='inner').drop('id_2')

After I've joined multiple tables together, I run them through a simple function to rename columns in the DF if it encounters duplicates. Alternatively, you could drop these duplicate columns too.

Where Names is a table with columns ['Id', 'Name', 'DateId', 'Description'] and Dates is a table with columns ['Id', 'Date', 'Description'], the columns Id and Description will be duplicated after being joined.

Names = sparkSession.sql("SELECT * FROM Names")
Dates = sparkSession.sql("SELECT * FROM Dates")
NamesAndDates = Names.join(Dates, Names.DateId == Dates.Id, "inner")
NamesAndDates = deDupeDfCols(NamesAndDates, '_')
NamesAndDates.saveAsTable("...", format="parquet", mode="overwrite", path="...")

Where deDupeDfCols is defined as:

def deDupeDfCols(df, separator=''):
    newcols = []

    for col in df.columns:
        if col not in newcols:
            newcols.append(col)
        else:
            for i in range(2, 1000):
                if (col + separator + str(i)) not in newcols:
                    newcols.append(col + separator + str(i))
                    break

    return df.toDF(*newcols)

The resulting data frame will contain columns ['Id', 'Name', 'DateId', 'Description', 'Id2', 'Date', 'Description2'].

Apologies this answer is in Python - I'm not familiar with Scala, but this was the question that came up when I Googled this problem and I'm sure Scala code isn't too different.