$a = array('one'=> val, 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten');
$b = array('four'=> val, 'one'=> val, 'eight'=> val, 'five'=> val)
I have two arrays as shown above.
need result like this:
will output:
'one' => val
'two' => 0
'three' => 0
'four' => val
'five' => val
'six' => 0
'seven' => 0
'eight' => val
'nine' => 0
'ten' => 0
Is there easy way to do this?
any help would be good
Actually array_intersect does something like this. It creates an new array out of these 2 arrays, only holding the values which are available in both arrays.
http://php.net/manual/en/function.array-intersect.php
array_intersect()returns an array containing all the values of array1 that are present in all the arguments. Note that keys are preserved.
edit: You should rather use array-diff,
Compares array1 against one or more other arrays and returns the values in array1 that are not present in any of the other arrays.
http://php.net/manual/en/function.array-diff.php
The code for your output described above would be something like:
<?php
$a = array('one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten');
$b = array('four', 'one', 'eight', 'five');
//Find matches and not matches
$matches = array_intersect($a, $b);
$dontmatches = array_unique(array_merge($a, $b));
//Set all dont matches to 0
for($i = 0; $i<count($dontmatches);$i++)
$dontmatches[$i] = 0;
$final = array_merge($matches, $dontmatches);
print_r($final);
?>
I used both described functions from above plus the following:
$a-array looks like'one'=>val, [0]=>two, [1]=>three..etc, you wish to compare slightly different array structures.