matching strings in scala

Question

I am trying to create a method that takes a list of lists (which reads from a csv file), and a string, and outputs a list of all the data that has that string.

Data example:

"Joe, 14,1989"
"John, 13,1999"
"Mary, 10, 2000"

the function I have is this:

def name(info: List[List[String]], str: String): List[List[String]] = 
info.filter(lst =>lst.head.toString == str)

However, I get an empty list in return. What is the best way to compare strings in scala?

Is info.head supposed to be List("joe","14","1989")? b/c yes "joe" == "joe" in scala. — som-snytt
– som-snytt, Commented Feb 10, 2016 at 0:03

Ben · Accepted Answer · 2016-02-09 23:55:58Z

2

Since you're calling .head, this will return only lists whose first element is equal to str. (It's also superfluous to call .toString, since the items are already strings.)

What you want is info.filter(lst => lst.contains(str)), or simply info.filter(_.contains(str)).

answered Feb 9, 2016 at 23:55

Ben

1,4722 gold badges13 silver badges19 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

matching strings in scala

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related