Unable to collect values from array URL in PHP

Question

3rd party passes the details to the URL. It makes get request to the URL with details as url-encoded HTTP query parameters.

following is the URL sample : http://_______.com/customer_missed_call.php?CallSid=e9536ef16460727558c0db17349021b0&From=09513325525&To=08039511763&Direction=incoming&DialCallDuration=0&StartTime=2016-02-10+14%3A56%3A17&EndTime=0000-00-00+00%3A00%3A00&CallType=callattempt&DialWhomNumber=&Created=Wed%2C+10+Feb+2016+14%3A56%3A17&flow_id=67475&tenant_id=24683&CallFrom=09513325525&CallTo=8039511763&ForwardedFrom=&CurrentTime=2016-02-10+14%3A56%3A17

I want to collect the values of 'CallSid' and 'From' from this url.

I tried following codes

<?php echo $_GET; ?>

and

<?php echo utf8_decode(urldecode($_GET)); ?>

and

$URL = $_SERVER['REQUEST_URI'];
  $parsedURL=parse_url($URL);
  $URLQ=$parsedURL['CallSid'];
  echo $parsedURL;

but did not got values for any one of the above code. Please try to give effective solution for the above problem. Thanks in advance.

I think your URL is corrupted shouldn't it start with http://_______.com/customer_missed_call.php?CallSid=... ? — Johannes Pichler
– Johannes Pichler, Commented Feb 10, 2016 at 9:52

SpongePablo · Accepted Answer · 2016-02-10 09:52:52Z

1

They are missing an ? after the .php

It should be like this:

http://_______.com/customer_missed_call.php?CallSid=e9536ef16460727558c0db17349021b0&From=09513325525&To=08039511763&Direction=incoming&DialCallDuration=0&StartTime=2016-02-10+14%3A56%3A17&EndTime=0000-00-00+00%3A00%3A00&CallType=callattempt&DialWhomNumber=&Created=Wed%2C+10+Feb+2016+14%3A56%3A17&flow_id=67475&tenant_id=24683&CallFrom=09513325525&CallTo=8039511763&ForwardedFrom=&CurrentTime=2016-02-10+14%3A56%3A17

answered Feb 10, 2016 at 9:52

SpongePablo

88810 silver badges24 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

vinit kantrod Over a year ago

question mark is there. i forgot to add it in code. but problem remains same

TheAlexLichter · Accepted Answer · 2016-02-10 23:58:50Z

1

The "?"-delimiter is missing in the URL

Edit: Please provide how you call the URL (the code for the request).

$_GET['CallSid']; should do the trick normally

edited Feb 10, 2016 at 23:58

answered Feb 10, 2016 at 9:52

TheAlexLichter

7,3328 gold badges50 silver badges76 bronze badges

1 Comment

vinit kantrod Over a year ago

the ? is there. But still unable to get the values?

Corvus Crypto · Accepted Answer · 2016-02-11 00:10:05Z

0

One of the things that is likely causing an issue is that parse_url returns an array with predefined keys. The key for the query is 'query' ($parsedURL['query'];)

However using the $_GET method is much more easy to read and is easier than getting the query string and manually parsing it. To access values in it, you also need to specify a key, not just call the array itself. e.g.:

$callSID = $_GET['CallSid'];
$from = $_GET['From'];

Hope that helps

answered Feb 11, 2016 at 0:10

Corvus Crypto

2,3011 gold badge16 silver badges14 bronze badges

Collectives™ on Stack Overflow

Unable to collect values from array URL in PHP

3 Answers 3

1 Comment

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

1 Comment

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related