Python check if string contains all words in Python

Question

I want to check if all words are found in another string without any loops or iterations:

a = ['god', 'this', 'a']

sentence = "this is a god damn sentence in python"

all(a in sentence)

should return TRUE.

this could help stackoverflow.com/questions/3389574/…

Allen Fernandes
– Allen Fernandes

2016-02-10 14:21:43 +00:00
Commented Feb 10, 2016 at 14:21 — Allen Fernandes
– Allen Fernandes, Commented Feb 10, 2016 at 14:21

Martin Evans · Accepted Answer · 2016-02-10 14:52:33Z

4

You could use a set depending on your exact needs as follows:

a = ['god', 'this', 'a']
sentence = "this is a god damn sentence in python"

print set(a) <= set(sentence.split())

This would print True, where <= is issubset.

edited Feb 10, 2016 at 14:52

answered Feb 10, 2016 at 14:32

Martin Evans

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1 Comment

Rolf of Saxony Over a year ago

You could drop the ' ' to become set(sentence.split())

Iron Fist · Accepted Answer · 2016-02-10 15:17:27Z

3

It should be:

all(x in sentence for x in a)

Or:

>>> chk = list(filter(lambda x: x not in sentence, a)) #Python3, for Python2 no need to convert to list
[] #Will return empty if all words from a are in sentence
>>> if not chk:
        print('All words are in sentence')

edited Feb 10, 2016 at 15:17

answered Feb 10, 2016 at 14:31

Iron Fist

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1 Comment

Iron Fist Over a year ago

That's part of all expression...nothing to do about it, but I don't believe that's part of OP concern...as he is avoiding any explicit for loop

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