json_decode() - syntax error

Question

I want to remove special chars (and found this in a forum):

$response = trim(preg_replace("#(/\*([^*]|[\r\n]|(\*+([^*/]|[\r\n])))*\*+/)|([\s\t]//.*)|(^//.*)#", '', $response));

The same for this

for ($i = 0; $i <= 31; ++$i) {
    $response = str_replace(chr($i), "", $response);
}

$response = str_replace(chr(127), "", $response);

if (0 === strpos(bin2hex($response), 'efbbbf')) {
    $response = substr($response, 3);
}

And this for encoding

$response = mb_convert_encoding($response, "UTF-8");
echo "\nJSON Response:#$response#\n";

At this point $response echoes:

{"data":{"taxa":[{"placa":"EDY8986","taxas_detran":"141.36","seguro_dpvat":"211.30","ipva":"1945.20","multas":"5048.10","total_debitos":"null"}]},"code":200,"pagination":{"rows":1,"page":1,"pages":0,"hasNext":false,"totalRows":1}}

In the end

$data = json_decode('"' . $response . '"',true, 512);
echo "\n\nData>\n";
print_r($data);
echo "\nError> "; echo json_last_error_msg();

json_last_error_msg() prints:

Syntax Error

I've already validated it in JSONLint and JSON Formatter and it is valid.

I can't believe it. Maybe i get crazy. Thanks man, its working! — João Pedro
– João Pedro, Commented Feb 11, 2016 at 18:26

Death-is-the-real-truth · Accepted Answer · 2016-02-11 18:39:16Z

2

You need to just littile bit change and it work fine:-

$data = json_decode($response,true, 512);// remove quotes

edited Feb 11, 2016 at 18:39

answered Feb 11, 2016 at 18:29

Death-is-the-real-truth

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Comments

Marc B · Accepted Answer · 2016-02-11 18:35:40Z

1

You're killing your JSON with the extra quotes:

 $data = json_decode('"' . $response . '"',true, 512);
                      ^-----------------^

Assuming your $response is

{"foo":"bar"}

Then you'd be producing/passing

"{"foo":"bar"}"

which is an outright JSON syntax error:

"{"foo":"bar"}"
^--start string
  ^-end string
   ^^^---????

answered Feb 11, 2016 at 18:35

Marc B

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