How generating route with parameters using Routing.generate in Symfony2?

Question

I'm trying to generate a path in an Ajax request, but I get the following error:

Error: The route "profesor_edit" requires the parameter "id".

The code is as follows:

$.ajax({
    type: 'POST',
    url: Routing.generate('verify_user'),
    data: {name:name},
    dataType: 'json',
    success: function(response) {

      if(response.data!=null){
          $("#container").load(Routing.generate('user_edit'), { id: response.data }); //"response.data" contains the value returned by the ajax call is an id value
      }
      else{
        $("#container").append("<span >It could not find the id</span>");        
      }   
    } 
  })

routing file:

user_edit:
     path:     /{id}/edit
     defaults: { _controller: "BackendBundle:User:edit" }

I think I will be sending the wrong parameter, but it's the only way I've ever seen. I appreciate your help.

if you use FOSRoutingBundle, its Routing.generate('user_edit', resonse.data) doku — mador
– mador, Commented Feb 12, 2016 at 12:19
Hi @dokumador, I tried your solution and now I get the following error: TypeError: invalid 'in' operand e. Would you know why that is? — Joseph
– Joseph, Commented Feb 12, 2016 at 12:41
Hi @mador, That contains a user id that is returned in the ajax call in the parameter "data" in this way: return new JsonResponse(array('data' =>$user->getId()), 200); — Joseph
– Joseph, Commented Feb 12, 2016 at 12:48

chalasr · Accepted Answer · 2016-02-12 12:57:10Z

3

Assuming you are using FOSJSRoutingBundle, use the following :

$("#container").load(Routing.generate('user_edit', { id: response.data }));

answered Feb 12, 2016 at 12:57

chalasr

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1 Comment

Joseph Over a year ago

Hi @chalasr, thanks for your answer, right now I had come to the same solution

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