In bash using sort with the -n option doesn't give me the expected result.
$ cat numbers | sort -n
1.0
1.1
1.11.4
1.15
1.3
1.3.3
1.4-p1
1.6.1
2.2.10
2.2.2
2.4
2.4.6
I tried using -k1, -k1.1n, etc. (-k1.3n gets the order correct only for numbers starting with 1). It seems there's something very basic I'm missing here...
There is a special flag for this -V for version numbers
$ sort -V numbers
1.0
1.1
1.3
1.3.3
1.4-p1
1.6.1
1.11.4
1.15
2.2.2
2.2.10
2.4
2.4.6
ps. this option is available in GNU Coreutils and may be missing in other implementations.
sort that comes with OS X actually is GNU sort, but it it is very old, and predates support for -V; as of OS X 10.11, the version number is sort (GNU coreutils) 5.93.
-V to macOS sort --version 2.3-Apple (99).sort -g numbers
It will do. As per sort man page, -g is meant for numerical sorting:
-g, --general-numeric-sort
compare according to general numerical value
You need the -t. flag to specify '.' as your separator, and the multiple key position specifiers handles the progressively longer/deeper numbers. I still don't quite understand exactly how it works, but it works ...
sort -t. -k 1,1n -k 2,2n -k 3,3n -k 4,4n numbers
or
cat numbers | sort -t. -k 1,1n -k 2,2n -k 3,3n -k 4,4n
Try;
sort -g -k1 file
It will definitely work!!!
