Int and String array in Java

Question

public class CHECK {
public CHECK(){
    String []wrkrs = {"Денис", "Саша", "Наталья", "Анатолий", "Юра", "Коля", "Катя", "Дима", "Антон","Тамара"};
    int [] wrkrsPhone = {22626,22627,22628,22629,22630,22631,22632,22633,22634,22635};
    String a = JOptionPane.showInputDialog(null, "Hello,friend!Do you wanna know, is that guy at work?Enter name:");


    if(Arrays.asList(wrkrs).contains(a)){
        JOptionPane.showMessageDialog(null, "That guy is at work!");
        JOptionPane.showMessageDialog(null, "calling " + wrkrsPhone[wrkrsPhone.toString().indexOf(a)]);
    }else{
        JOptionPane.showMessageDialog(null, "Такого сотрудника нет!");
    }
}

I have two arrays, which contain ints and strings. As you can see, I want to add the number of elements in the string array (for example, wrkrs number 3) to the int array, called wrkrs phone. How can i do it? I tried IndexOf, but it doesn't work.

The output, i want is something like:

Enter name:
Юра
That guy is at work!
Calling Юра + wrkrsPhone(Юра).

Eran · Accepted Answer · 2016-02-14 11:26:48Z

5

A better solution would be to have a Worker class that would contain the worker's name and their phone number.

Then you can use a HashMap<String,Worker> instead of your arrays to store the data.

This makes the search more efficient :

Map<String,Worker> workersMap = new HashMap<>();
workersMap.put ("Денис", new Worker ("Денис", 22626));
...
Worker worker = workersMap.get(a);
if (worker != null) {
    call (worker.getPhone()); // or do whatever you want to do with the phone number
}

This is more efficient than Arrays.asList(wrkrs).contains(a), which performs linear search on the List.

edited Feb 14, 2016 at 11:26

answered Feb 14, 2016 at 11:18

Eran

395k57 gold badges726 silver badges793 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Lame Lane Over a year ago

Thank you! I haven't worked with MAP, but i'll do it soon)

Csed Third · Accepted Answer · 2016-02-14 13:37:46Z

-1

...
List list = Arrays.asList(wrkrs);
if(list.contains(a)){
    JOptionPane.showMessageDialog(null, "That guy is at work!");
    JOptionPane.showMessageDialog(null, "calling " + wrkrsPhone[list.indexOf(a)]);
}
...

U better use a Map or extract a class Contact which have name and phone property but i think this is what u looking for :)

answered Feb 14, 2016 at 13:37

Csed Third

14

1 Comment

Lame Lane Over a year ago

Thank you! I'll try it!)

Collectives™ on Stack Overflow

Int and String array in Java

2 Answers 2

1 Comment

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related