I am trying to pull the largest number of an array using a forEach Javascript method. This is what I have so far, but I know it's not correct.
var arr = [2,3,4];
var largest = 0;
arr.forEach(function(elem){
if(largest < elem)
largest = elem;
console.log(largest);
});This will work
var arr = [2,3,4];
var largest = 0;
arr.forEach(function(elem){
if(largest < elem)
largest = elem;
});
console.log(largest);
but why would you even do that? Why not use Math max?
var largest = Math.max.apply(Math, arr);
To cover negative numbers in array, it is safe to assign largest to be the first element in array.
var arr = [2,3,4];
var largest = arr[0];
arr.forEach(function(elem){
if(largest < elem)
largest = elem;
});
console.log(largest);You can simply use spread operator:
var arr = [2,3,4];
var largest = Math.max(...arr);
console.log(largest);If you put console.log(largest); outside forEach loop, it will print the largest number in the array.
var
a = [2,3,4,2,1,9],
largest = 0;
a.forEach(function(value){
console.log('current array element value: ' + value + '. Is it larger than the largest?', (largest > value));
if (largest < value) largest = value;
console.log('largest value now is: ', largest);
});
console.log('largest is changed here, because it was not redefined inside the function of the forEach method: ', largest, '.\n But it was defined within its context.');
function greatest(array) {
if(array == undefined){
console.log('There are no elements in array.');
}
const max = array.reduce(function(first, next){
return first > next ? first : next;
});
console.log(`Maximum element is ${max}`);
}