How to read the below xml using php?
<?xml version="1.0" encoding="UTF-8"?>
<video>
<youtube> youtube video url </youtube>
</video>
I tried the code below but seems not working:
$dom = new DOMDocument();
$dom->load('new_result.xml');
$results = $dom->documentElement;
foreach( $results as $result)
{
foreach( $result->getElementsByTagName('youtube') as $youtube )
{
echo ' video url ' . $youtube->nodeValue;
}
}
try this :
if (file_exists('result.xml')) {
$xml = simplexml_load_file('result.xml');
echo $xml->youtube;
} else {
exit('Failed to open result.xml.');
}
youtube element in the whole XML, of course.No need for anything fancy, just use ->getElementsByTagName() method after you've loaded it up:
$dom->load('new_result.xml'); // load the file
// use ->getElementsByTagName() right away
$youtube = $dom->getElementsByTagName('youtube');
if($youtube->length > 0) { // if there are youtube nodes indeed
foreach($youtube as $y) { // for each youtube node
echo $y->nodeValue;
}
}
The DOMDocument::documentElement is the root element node. In your XML, this would be the video element node. It is not a node list, but the actual node, so foreach will not work.
Just remove the outer foreach
$dom = new DOMDocument();
$dom->load('new_result.xml');
$video = $dom->documentElement;
foreach($video->getElementsByTagName('youtube') as $youtube) {
echo ' video url ' . $youtube->nodeValue;
}
If you XML gets more complex you can use Xpath expressions:
$dom = new DOMDocument();
$dom->load('new_result.xml');
$xpath = new DOMXpath($dom);
foreach($xpath->evaluate('/video/youtube') as $youtube) {
echo ' video url ' . $youtube->nodeValue;
}
Most Xpath expression will return node lists, but they can return scalar values. With that you can eliminate the second loop, too:
$dom = new DOMDocument();
$dom->load('new_result.xml');
$xpath = new DOMXpath($dom);
echo ' video url ' . $xpath->evaluate('string(/video/youtube[1])');
