How do I write a numpy array into a file in a string form?

Question

I have a numpy array like this:

 n=   [['20015' '20013' '20044' '20001' '20002']
     ['20002' '20015' '20001' '20013' '20070']
     ['20044' '20013' '20015' '20001' '20002']
     ['20071' '20015' '20070' '20001' '20002']]

I wish to print this list into a file in the form of :

20015, 20013, 20044, 20001, 20002
 20002, 20015, 20001, 20013, 20070

How can I get rid of the list of list but still keep the grouped 5 together: I tried this out:

    f=open("myfile.txt, "w")
    n=clf.classes_[order[:, -5:]]
    print(n)
    str1=''.join(str(x) for x in n)
    print>>f, str1
    f.close()

But this again puts them in a list.

Bob Dylan · Accepted Answer · 2016-02-19 15:08:21Z

2

If I'm understanding correctly, you just want to print the elements as shown in your question. This should work:

with open("myfile.txt", "w") as f:
    for row in n:
        s = ', '.join(str(x) for x in row)
        f.write(s)
        f.write("\n")

answered Feb 19, 2016 at 15:08

Bob Dylan

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Noctis Skytower · Accepted Answer · 2016-02-19 16:05:43Z

2

This should do what you asked for:

>>> n = [[20015, 20013, 20044, 20001, 20002],
     [20002, 20015, 20001, 20013, 20070],
     [20044, 20013, 20015, 20001, 20002],
     [20071, 20015, 20070, 20001, 20002]]
>>> with open('myfile.txt', 'w') as file:
    for row in n:
        print(*row, sep=', ', file=file)

>>>

Proving that it works properly is simple:

>>> print(open('myfile.txt').read())
20015, 20013, 20044, 20001, 20002
20002, 20015, 20001, 20013, 20070
20044, 20013, 20015, 20001, 20002
20071, 20015, 20070, 20001, 20002

>>>

answered Feb 19, 2016 at 16:05

Noctis Skytower

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M.T · Accepted Answer · 2016-02-19 15:08:33Z

1

Try this

text = '\n'.join(', '.join(ni) for ni in n)
with open('myfile.txt','w') as f:
    f.write(text)

answered Feb 19, 2016 at 15:08

M.T

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