How To Insert Data Using Multiple Input With Same Name in codeigniter

Question

I'm using JavaScript would produce the following entries

<input type="hidden" name="my_img[]" value="dad6e52b274690409835.jpg">
<input type="hidden" name="my_img[]" value="252529b6e21f872c7675.jpg">
<input type="hidden" name="my_img[]" value="3cce4128c366216fsfaf.jpg">
<input type="hidden" name="my_img[]" value="48697e8516caa3cc15d4.jpg">

But I've had trouble inserting them in the database

my controllers :

   $dd=$this->input->post('my_img');
   for($i=0;$i<count($dd);$i++)
   {
   $img_box[$i] = array ('img_url' => $dd[$i]);
   }
   $this->posts_model->add_new_ads_img($img_box);

my model :

public function add_new_ads_img($img_box)
{
    $q = $this->db->insert('advertise_gallery',$img_box);
    if ($q)
    {
        return TRUE;
    }
    else return FALSE;
}

And to eat error

Severity: Notice

Message: Undefined variable: img_box

Please guide me

$img_box only lives within the for loop scope. Define it outside of the loop like this: $img_box = array(); — Glubus
– Glubus, Commented Feb 19, 2016 at 15:32

Thomas Ghesquiere · Accepted Answer · 2016-02-19 15:32:00Z

4

The error could be this line in your controller:

$img_box[$i] = array ('img_url' => $dd[$i]);

Just before your for-loop add:

$img_box = [];

answered Feb 19, 2016 at 15:32

Thomas Ghesquiere

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6 Comments

Glubus Over a year ago

I think newer versions of php prefer = array() over = [] (not that it matters too much for this question)

Thomas Ghesquiere Over a year ago

Only newer versions support [], previously you had to use array(). (Since 5.4 I think)

Glubus Over a year ago

Ah that makes sense.

amir.01 Over a year ago

tnx fix it but now have other problem i have 10 input but i print_r($img_box); show >>> arry() is empty and echo count($dd) show >>> 0

Thomas Ghesquiere Over a year ago

If count($dd) === 0, it seems that you did not post your page. If you comment out your code controller code except for the $dd=$this->input->post('my_img');, is the count different?

|

devSouth555 · Accepted Answer · 2016-02-19 15:47:17Z

0

Based on what I think you are trying to do, you could try to give each input a different id. That way you could insert based on the id name.

for exampe:

    <input type="hidden" name="my_img[]" id="img1" value="dad6e52b274690409835.jpg">
<input type="hidden" name="my_img[]" id = "img2" value="252529b6e21f872c7675.jpg">
<input type="hidden" name="my_img[]" id = "img3" value="3cce4128c366216fsfaf.jpg">
<input type="hidden" name="my_img[]" id = "img4" value="48697e8516caa3cc15d4.jpg">

if you need to add them to an array, you can do so in the java script

var img=[$('#img1').val(),$('#img2').val(),$('#img3').val()]

Hope this helps

answered Feb 19, 2016 at 15:47

devSouth555

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1 Comment

amir.01 Over a year ago

No I want all entries are sent with a one name

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