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Given a list/array of elements, such as [0, 1, 2], what is the most numpythonic way to replicate each element n times and store the result in a 1-d array, such as (for n=3) [0, 0, 0, 1, 1, 1, 2, 2, 2]?

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Use np.repeat:

In [86]: np.repeat([0, 1, 2], 3)
Out[86]: array([0, 0, 0, 1, 1, 1, 2, 2, 2])
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I knew I missed the obvious solution. Thanks!

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