Error for python

Question

Ok i have an if then statement and i want it to display something if the user clicks Yes or No and if they enter something except YES OR NO then it gives an error. But when i do it, i put it in a print variable but even though they put something else it still goes on. Here is the code.

drink = raw_input("Do you want a drink?")
if (drink =="Yes" or drink =="yes"):
    print ("Soda\n Coffee \n Latte\n or Smoothie")
    drink1 = raw_input("What type of drink will you like?")
    print (drink1," coming up")
else:
    print ("Error")

idjaw · Accepted Answer · 2016-02-22 02:15:44Z

6

Because your condition only has a condition for yes. So even if you take no as input, you will still go in to the error condition. You need an extra elif to handle the "no" case.

Also, just cast drink to lower and always check it for one case: "yes":

drink = raw_input("Do you want a drink?").lower()
if (drink == "yes"):
    print ("Soda\n Coffee \n Latte\n or Smoothie")
    drink1 = raw_input("What type of drink will you like?")
    print (drink1," coming up")
elif (drink == "no"):
    print("you do not want a drink")
    # do things for no here
else:
    print ("Error")

edited Feb 22, 2016 at 2:15

answered Feb 22, 2016 at 0:59

idjaw

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8 Comments

Jon2713 Over a year ago

what does the ".lower" do lol. Sorry we haven't learned that yet in class

Koga Over a year ago

.lower converts all the letters to lowercase in a specified string.

idjaw Over a year ago

^^Yup. That would be it.

Jon2713 Over a year ago

so its redundant to put like (blah =="yes" or blah=="Yes")

idjaw Over a year ago

@SeanBallais You're absolutely right. Silly mistake. I corrected my solution. Thanks.

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