execute printf command shell script

Question

I am a beginner in writing shell script (probably my 1st shell script). I have a shell script that I like to run. The command is a simple grep command based on the parameter passed to it. I managed to get the correct grep command using the script below.

FILE='testurls'
MERCHANT_ID='8'
printf "grep '^%s' %s\n" "$MERCHANT_ID" "$FILE"

./hello.sh 
grep '^8' testurls

How would I execute the command instead of printing it.

Aside: By convention, environment variables (PATH, EDITOR, SHELL, ...) and internal shell variables (BASH_VERSION, RANDOM, ...) are fully capitalized. All other variable names should be lowercase. Since variable names are case-sensitive, this convention avoids accidentally overriding environmental and internal variables. — Rany Albeg Wein
– Rany Albeg Wein, Commented Feb 22, 2016 at 10:52

ceving · Accepted Answer · 2016-02-22 09:55:17Z

2

printf is not necessary

FILE='testurls'
MERCHANT_ID='8'
grep "^$MERCHANT_ID" "$FILE"

answered Feb 22, 2016 at 9:55

ceving

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Siddharth sharma · Accepted Answer · 2016-02-22 09:59:53Z

2

You can use shell backticks quotes. This will store the output of executable commands.

Syntax are :-

1) Legacy Bourne shell backticks ``:

var=`grep "^$MERCHANT_ID" "$FILE"` 
printf "%s\n" "$var"

2) $() syntax:

var=$(grep "^$MERCHANT_ID" "$FILE")
printf "%s\n" "$var"

answered Feb 22, 2016 at 9:59

Siddharth sharma

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