Calling PHP functions through AJAX using jQuery callback parameters

Question

I have problems with AJAX results using jQuery.

I have defined these functions:

<script>
    function hello(callback, funct, val) {
        var ret = 0;
        console.log(val);
        $.ajax({
            type: 'GET',
            dataType: 'json',
            url: 'SGWEB/header.php',
            data: {
                'funct': funct,
                'val': val
            }
        }).done(function (data) {
            // you may safely use results here
            console.log(data);
            callback(data);
        });
    };

    function change() {
        hello(function (ret) {
                  console.log(ret);
                  $("#b1").text(ret);
              }, "hello", 1);
    }; 

    change();
</script>

SGWEB/header.php:

extract($_GET);
$validFunctions = array("readPin","hello");
if(in_array($funct, $validFunctions)) $funct();

// functions
// ....

function hello($val) {
    if ($val == 1) {
        echo "1";
    } else 
        echo "2";
}

The problem I have is that the AJAX passes only the first parameter in data {'funct': funct} and it's working, but val is completely ignored (it always echoes "2").

How can I solve this? Thanks

You pass a function to hello() which is false when you compare it to 1.. that's why it always goes to the else branch. — A1rPun
– A1rPun, Commented Feb 22, 2016 at 14:20
@A1rPun javascript hello function (top of code) expects a callback function as it's first argument... the hello function at the bottom of code is a PHP function (I think) — Jaromanda X
– Jaromanda X, Commented Feb 22, 2016 at 14:30
I'd like to see more of SGWEB/header.php to see how it's handling the incoming query to end up calling the hello function ... surely the code marked PHP function isn't the whole content of that header.php — Jaromanda X
– Jaromanda X, Commented Feb 22, 2016 at 14:31
You need to add the proper PHP. I dont see the contents of SGWEB/header.php and I dont see how you are obtaining your GET data in PHP. — CodeGodie
– CodeGodie, Commented Feb 22, 2016 at 14:38

CodeGodie · Accepted Answer · 2016-02-22 15:33:01Z

3

You are forgetting to pass the $val parameter to your function in PHP

Change this:

if (in_array($funct, $validFunctions)) $funct();

to this:

if (in_array($funct, $validFunctions)) $funct($val);

Another problem is that your AJAX is expecting JSON as you are defining it here dataType:'json' but you are not sending that. I would redo your ajax call like this so that you can see other errors as well:

$.ajax({
    type: 'GET',
    url: 'SGWEB/header.php',
    data: {
        'funct': funct,
        'val': val
    },
    success: function (result) {
        console.log(result);
        callback(result);
    },
    error: function (xhr, textStatus, error) {
        console.log(xhr);
        console.log(textStatus);
        console.log(error);
    }
});

edited Feb 22, 2016 at 15:33

answered Feb 22, 2016 at 15:21

CodeGodie

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7 Comments

Ghesio Over a year ago

Thanks a lot, my error was a little dumb. Tried the PHP side of the answer and is working, tomorrow I'll try the JS code!

CodeGodie Over a year ago

awesome, glad i was able to help

Ghesio Over a year ago

Hi again... do you also know how can I use this type of ajax function in a for loop? can provide code if needed. Thanks

CodeGodie Over a year ago

Yea, but if you can provide code, it would be best so that I can see what you mean.

CodeGodie Over a year ago

I see, are you getting any errors on your console? Also, I would post a new question with this information. Would you be able to do that?

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