Iterating through an ArrayList of different objects [duplicate]

Question

I have an abstract class with several subclasses. A tester class has an ArrayList with 1 object of each subclass in it. They each have a method of the same name, how can I iterate through the ArrayList and call that method for each object?

One of my subclasses (others basically the same):

public class MyMath extends Homework {
private int pagesRead;
private String typeHomework;

public MyMath(int pagesRead, String typeHomework) {
    super(pagesRead, typeHomework);
}

public void createAssignment(int p) {
    setPagesRead(p);
    setTypeHomework(typeHomework);
}

public void toString(int pagesRead, String typeHomework) {
    System.out.println("Homework type: " + typeHomework + ". Number of pages read: " + pagesRead + ".");
}

}

In my tester class main method:

ArrayList homework = new ArrayList();
homework.add(new MyMath(5, "Math"));
homework.add(new MyScience(5, "Science"));
homework.add(new MyEnglish(5, "English"));
homework.add(new MyJava(5, "Java"));

Does the abstract class also have a method with the same name (and parameter types)? — markspace
– markspace, Commented Feb 23, 2016 at 4:41
The abstract class has an abstract method that each subclass overrides. — Stephanie Fu
– Stephanie Fu, Commented Feb 23, 2016 at 4:45
Then any list iteration (for-each, plain for loop, etc.) should work fine, as given in both answers below. — markspace
– markspace, Commented Feb 23, 2016 at 4:47

Michael · Accepted Answer · 2016-02-23 04:42:22Z

1

Well, if the method is specified in your abstract class, and you have already built the ArrayList with all the objects inside it, you should simply be able to iterate through the ArrayList (for-loop) and just call the .method()

answered Feb 23, 2016 at 4:42

Michael

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6 Comments

Stephanie Fu Over a year ago

Can I use a foreach loop, or does that not work on this because they are different types of objects?

markspace Over a year ago

The for-each construct should work fine.

Michael Over a year ago

Yes, as markspace has said, the for-each construct should work! I was just giving an example of a way to iterate through the ArrayList

Calvin P. Over a year ago

@StephanieFu As long as the objects have already been initialized, I should think you could use a for each such as for(SuperClass a : list) and in the loop, a.method();.

Stephanie Fu Over a year ago

@CalvinP. I tried doing that, and I got a "Type mismatch: cannot convert from element type Object to Homework" error. Homework is the superclass.

|

timothyjosefik · Accepted Answer · 2016-02-23 04:46:07Z

0

If your ArrayList is of type and your interface also has the method then you can call them like so

for(int i = 0; i < list.length();i++)
{
    list[i].METHOD_NAME();
}

answered Feb 23, 2016 at 4:46

timothyjosefik

1266 bronze badges

Comments

user2326210 · Accepted Answer · 2016-02-23 04:47:47Z

0

You can iterate through the arraylist ant it contains objects and you can call the method on that object. for example,

ArrayList<AbstractClass1> objs = new ArrayList<AbstractClass1>();

objs.add(); // you have added objects already.

Then

for(int i = 0; i< objs.size() ; i++){

objs.get(i).methodYouDefined();

}

answered Feb 23, 2016 at 4:47

user2326210

Comments

markspace · Accepted Answer · 2016-02-23 04:55:20Z

If you haven't covered generics yet in class, you have to cast manually. If you have covered generics, you should use them! See lak91's answer.

public abstract class AbstractTest
{
   public abstract void oneTwo( int i, String s );

   public static void main(String[] args) {
      List list = new ArrayList();
      list.add( new One() );
      list.add( new Two() );
      for( Object test : list ) {
         AbstractTest abTest = (AbstractTest) test;
         abTest.oneTwo( 0, "test" );
      }
   }

}

class One extends AbstractTest {

   @Override
   public void oneTwo( int i, String s )
   {
      System.out.println("One");
   }

}

class Two extends AbstractTest {

   @Override
   public void oneTwo( int i, String s )
   {
      System.out.println("Two");
   }

}

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