3

I am in a very specific situation where I have an indexed array $name_array, which have 0 index but don't have values, as follow;

Array
(
    [0] => 
)

I want to consider this array as empty, I've checked it in isset($name_array) and !empty($name_array) but this array is passing both condition. I don't know What condition should I apply to detect if this array has these kind of values then it is empty?

for eg; 

if(/*some condition*/($name_array)) 
{
    echo 'I am not empty';
}
else
{
    echo 'I am empty';
}
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5
  • 7
    Possible duplicate of How to check if an array contains empty elements? Commented Feb 26, 2016 at 9:41
  • @Apb No, its not duplicate of above question, Both questions are completely different. Commented Feb 26, 2016 at 9:43
  • There are many links related to your question on SO. Google it. Commented Feb 26, 2016 at 9:47
  • stackoverflow.com/questions/5040811/… Commented Feb 26, 2016 at 9:49
  • 1
    $name_array = array_filter($name_array); Commented Feb 26, 2016 at 9:50

5 Answers 5

Reset to default
11

You can use array_filter:

if (!array_filter($name_array)) {
    // empty or has "empty" values
}

By default array_filter filters out any "empty" values like empty string, null or false.

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1 Comment

Yeah I changed It as if (array_filter($name_array)) { echo 'I am not empty'; } else { echo 'I am empty'; } working as expected.
2

!empty is enough to check your first index of array is valid or not:-

if(!empty($array[0])){
 // $array[0] has value
}

In case of Multidimensional array where you don't know first index key,

if(!empty($array[key($array)])){
  echo $array[key($array)];
}

empty - Returns FALSE if var exists and has a non-empty, non-zero value. Otherwise returns TRUE.

The following things are considered to be empty:

"" (an empty string)

0 (0 as an integer)

0.0 (0 as a float)

"0" (0 as a string)

NULL

FALSE

array() (an empty array)

$var; (a variable declared, but without a value)

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2 Comments

@devpro: In question, OP has defined index [0] of array. So I have suggested this way :)
yes, thats way i said, solution is fine... not ideal :)
0

There is no built-in function to check that
you can create your own instead :) here an example

function is_array_empty($name_array) {
    foreach($name_array as $elm) {
        if(!empty($elm)) return FALSE;
    }
    return TRUE;
}
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Comments

0

Are you only trying to check if the first element is empty? if so:

if ( ! current($name_array)) {
    // first element in $name_array is niether false, null, 0 or an empty string
}

if you need to check a more specific case, just change the exclamation mark into whatever it is you need checked.

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Comments

0 
function is_array_empty($name_array) {
    $arrSize=sizeof($name_array);
    $emptElements=0;
    foreach($name_array as $elm) {
        if(empty($elm)){
           $emptElements++;
        }
    }
    if($emptElements==$arrSize){
        return TRUE;
    }else{
        return FALSE;
    }
}
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1 Comment

too long... check @ksimka's answer.

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