Removing certain strings from array

Question

Good afternoon,

I am having some issues figuring out exactly how to remove a list of items from an array if they match my criteria inside of my program. Example is below. I want to remove anything that has admin in it, regardless of case, as well as anything in a list of names.

#This array is a list of user name
declare -a userList=($(command to get users))

#now my userList array is filled with different usernames
#ex = user01 user02 user03 admin user04 Admin_user AdMiN-account user09
#I have a second list of names that I want to remove from the array stored in a variable. Pseudocode is below. test.txt contains **user01 and user02**

for i in ${exclude} ; do
remove name from array
done
code to remove any spelling of admin from userList array.

If a longer explanation is needed please let me know. Thank you.

Possible duplicate of bash: how to delete elements from an array based on a pattern — miken32
– miken32, Commented Feb 29, 2016 at 21:28
Yes I have looked at that one. Does not explain how to disregard case and shows how to remove a single item such as pref instead of removing all items from another array or file... — IT_User
– IT_User, Commented Feb 29, 2016 at 21:31
Did you look at the answers? Like, this one: stackoverflow.com/a/31125399/1255289 — miken32
– miken32, Commented Feb 29, 2016 at 21:35
With GNU bash 4: declare -l -a array=(ABC DEF GHI); declare -p array and help declare — Cyrus
– Cyrus, Commented Feb 29, 2016 at 21:36
Yes I did Mike. His answer he shows how to take inside of a function to remove it from an array. I tried to implement something along his lines but was unable to get it to work for my situation — IT_User
– IT_User, Commented Feb 29, 2016 at 21:46

anubhava · Accepted Answer · 2016-02-29 21:33:48Z

2

Assuming you don't have newline in array elements, you can use grep for case-ignore removal of array entries:

arr=(user01 user02 user03 admin user04 Admin_user AdMiN-account user09)

sarr=($(grep -iv 'admin' <(printf "%s\n" "${arr[@]}")))

Check output:

declare -p sarr
declare -a sarr='([0]="user01" [1]="user02" [2]="user03" [3]="user04" [4]="user09")'

answered Feb 29, 2016 at 21:33

anubhava

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1 Comment

IT_User Over a year ago

Thank you very much, I did not even think of something as simple as grep for this case. Perfect answer on the removing admin. Thank you!.

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