Python/Django render enumerated list to table

Question

So for a project i'm working on, i want to return data into a table. It is basically this query that gets the data:

search_result = sp.search(q=search_query, limit=20)

        response = []
        for i, t in enumerate(search_result['tracks']['items']):
            response += i, t['name']

And in the template I try to display the data from the response as follow

<tbody>
    {% for data in response %}
  <tr>
    <td>{{data}}</td>
  </tr>
  {% endfor %}
</tbody>

Only the data is now being display in a wrong way:

------------------------
0
------------------------
[data here]
------------------------
1
------------------------
[data here]

I just started programming in python/django, so I am not sure how to display it in a way that the number and data are on the same row, or if I can display it without the integer

Daniel Roseman · Accepted Answer · 2016-03-06 18:46:31Z

2

There's no need that loop in the view. The whole thing should be done in the template. Just send the tracks data directly to the template, and use forloop.counter:

{% for data in tracks %}
  <tr>
    <td>{{ forloop.counter }}</td> <td>{{ data }}</td>
  </tr>
{% endfor %}

answered Mar 6, 2016 at 18:46

Daniel Roseman

602k68 gold badges910 silver badges923 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Python/Django render enumerated list to table

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related