Incorrect Regex Expression

Question

I found this site: https://mathiasbynens.be/demo/url-regex and wanted to use for my url validation the regex from the @diegoperini, because according to the table provided on the top of the site, it is the best regex.

When I try to use it, I get a range value error.

P.S. I am using the following Regex expression:

_^(?:(?:https?|ftp):\/\/)(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)(?:\.(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)*(?:\.(?:[a-z\x{00a1}-\x{ffff}]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?$_iuS

and the following online validator: http://regexr.com/

It does show the error place in the regex, but I don't know how to manage it. I tried to swap the both ranges, but it doesn't do the trick.

I would appreciate some help.

P. P. S. I use the regex in the AngularJS directive to validate url input.

What is your regex flavor? (language you are in)

Jorge Campos
– Jorge Campos

2016-03-07 15:13:49 +00:00
Commented Mar 7, 2016 at 15:13 — Jorge Campos
– Jorge Campos, Commented Mar 7, 2016 at 15:13
Javascript, I try to use it in the angularJS directive

N.Zukowski
– N.Zukowski

2016-03-07 15:14:34 +00:00
Commented Mar 7, 2016 at 15:14 — N.Zukowski
– N.Zukowski, Commented Mar 7, 2016 at 15:14

Bohemian · Accepted Answer · 2016-03-07 15:30:16Z

1

Buried within your character classes, you have this range:

\x{00a1}-\x{ffff}

But it should be:

\u00a1-\uffff

Your expression \x{00a1}-\x{ffff} is not the correct syntax for a hex encoding or a character and as-is means any of "x{}0a1f" plus the range "}-x", but "x" is less than "}" so an error is raised to that effect.

edited Mar 7, 2016 at 15:30

answered Mar 7, 2016 at 15:18

Bohemian♦

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5 Comments

Wiktor Stribiżew Over a year ago

In JS, \x requires 2 digit hex code, not 4. \xffff matches an \xff and 2 fs.

Bohemian Over a year ago

@WiktorStribiżew thank you for that info. I've changed the proposed fix to \u

N.Zukowski Over a year ago

Somehow I cannot get none of those regex (from the provided link) running. Probably they are all for php, not for js. I will use the standard angular url verification.

N.Zukowski Over a year ago

Is this Regex no correct @Bohemian? _^(?:(?:https?|ftp):\/\/)(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?$_iuS

Bohemian Over a year ago

@siri well that has the change, but it will never match anything due to the first 2 chars being _^, which is an impossible case (by definition, nothing comes before start)

adrisons · Accepted Answer · 2021-06-09 12:51:55Z

0

This should work

^(?:(?:https?|ftp):\/\/)(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?$

answered Jun 9, 2021 at 12:51

adrisons

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